Interpretation Introduction To determine: The speed of a proton having de Broglie wavelength of 122 pm . Explanation Given: The de Broglie wavelength ( λ ) of a proton is 122 pm . Explanation: The de Broglie equation is given as follows: λ = h m v Here, λ is the de Broglie wavelength, h is Planck’s constant, m is the mass of the subatomic particle, and v is the velocity. The mass of proton is 1.672 × 10 − 27 kg and value of Planck’s constant is 6.626 × 10 − 34 kg m 2 s − 1 . Substitute the values in the above equation: 122 pm = 6.626 × 10 − 34 kg m 2 s − 1 1.676 × 10 − 27 kg × v v = 6.626 × 10 − 34 kg m 2 s − 1 1

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Chapter 7, Problem 52E

Interpretation Introduction

To determine: The speed of a proton having de Broglie wavelength of 122 pm.

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Chapter 7, Problem 51E

Chapter 7, Problem 53E

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Chemistry: A Molecular Approach, Books a la Carte Plus Mastering Chemistry with Pearson eText -- Access Card Package (4th Edition)

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