To determine when writing the chemical equation for a reaction, how do you indicate that a given reactant is dissolve in water and formed a precipitate. Concept Introduction: A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction. For example, the reaction between lead sulphide and oxygen is as follows: 2 PbS+3 O 2 → 2 PbO+ 2 SO 2 Reactants Products In the given reaction, the number of all atoms, on the both side are equal hence this is a balance reaction. The most common driving forces which create product in chemical reactions are as follows: Formation of a solid. Formation of water. Transfer of electrons. Formation of gas. If a substance is not soluble in water than it forms precipitate. The phase of the precipitate is solid. The precipitates are formed depending on the solubility of salt in water.
To determine when writing the chemical equation for a reaction, how do you indicate that a given reactant is dissolve in water and formed a precipitate. Concept Introduction: A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction. For example, the reaction between lead sulphide and oxygen is as follows: 2 PbS+3 O 2 → 2 PbO+ 2 SO 2 Reactants Products In the given reaction, the number of all atoms, on the both side are equal hence this is a balance reaction. The most common driving forces which create product in chemical reactions are as follows: Formation of a solid. Formation of water. Transfer of electrons. Formation of gas. If a substance is not soluble in water than it forms precipitate. The phase of the precipitate is solid. The precipitates are formed depending on the solubility of salt in water.
Solution Summary: The author explains that a balanced chemical equation contains the same number of atoms as well as of each element of reactants and products of reaction.
Definition Definition Transformation of a chemical species into another chemical species. A chemical reaction consists of breaking existing bonds and forming new ones by changing the position of electrons. These reactions are best explained using a chemical equation.
Chapter 7, Problem 4QAP
Interpretation Introduction
Interpretation:
To determine when writing the chemical equation for a reaction, how do you indicate that a given reactant is dissolve in water and formed a precipitate.
Concept Introduction:
A balanced chemical equation is an equation that contains same number of atoms as well as of each element of reactants and products of reaction.
For example, the reaction between lead sulphide and oxygen is as follows:
2 PbS+3 O2→2PbO+2SO2 Reactants Products
In the given reaction, the number of all atoms, on the both side are equal hence this is a balance reaction.
The most common driving forces which create product in chemical reactions are as follows:
Formation of a solid.
Formation of water.
Transfer of electrons.
Formation of gas.
If a substance is not soluble in water than it forms precipitate. The phase of the precipitate is solid. The precipitates are formed depending on the solubility of salt in water.
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…
Chapter 7 Solutions
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