(a) Interpretation: The given oxidation-reduction reaction is to be balanced. Concept Introduction: In a chemical equation when the number of atoms of an element on the left-hand side is equal to the number of atoms of that element on the right-hand side, it is known as a balanced chemical equation. The balancing of a chemical equation is done to follow the law of conservation of mass.
(a) Interpretation: The given oxidation-reduction reaction is to be balanced. Concept Introduction: In a chemical equation when the number of atoms of an element on the left-hand side is equal to the number of atoms of that element on the right-hand side, it is known as a balanced chemical equation. The balancing of a chemical equation is done to follow the law of conservation of mass.
Solution Summary: The author explains that the oxidation-reduction reaction is to be balanced. The balancing of a chemical equation follows the law of conservation of mass.
Definition Definition Chemical reactions involving both oxidation and reduction processes. During a redox reaction, electron transfer takes place in such a way that one chemical compound gets reduced and the other gets oxidized.
Chapter 7, Problem 49QAP
Interpretation Introduction
(a)
Interpretation:
The given oxidation-reduction reaction is to be balanced.
Concept Introduction:
In a chemical equation when the number of atoms of an element on the left-hand side is equal to the number of atoms of that element on the right-hand side, it is known as a balanced chemical equation. The balancing of a chemical equation is done to follow the law of conservation of mass.
Interpretation Introduction
(b)
Interpretation:
The given oxidation-reduction reaction is to be balanced.
Concept Introduction:
In a chemical equation when the number of atoms of an element on the left-hand side is equal to the number of atoms of that element on the right-hand side, it is known as a balanced chemical equation. The balancing of a chemical equation is done to follow the law of conservation of mass.
Interpretation Introduction
(c)
Interpretation:
The given oxidation-reduction reaction is to be balanced.
Concept Introduction:
In a chemical equation when the number of atoms of an element on the left-hand side is equal to the number of atoms of that element on the right-hand side, it is known as a balanced chemical equation. The balancing of a chemical equation is done to follow the law of conservation of mass.
Interpretation Introduction
(d)
Interpretation:
The given oxidation-reduction reaction is to be balanced.
Concept Introduction:
In a chemical equation when the number of atoms of an element on the left-hand side is equal to the number of atoms of that element on the right-hand side, it is known as a balanced chemical equation. The balancing of a chemical equation is done to follow the law of conservation of mass.
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…
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