UNDERSTANDING THE UNIVERSE(LL)-W/CODE
3rd Edition
ISBN: 9780393869903
Author: PALEN
Publisher: NORTON
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Question
Chapter 7, Problem 42QAP
(a)
To determine
The temperature of the planet if albedo is
(b)
To determine
The average temperature of the planet if albedo is
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Chapter 7 Solutions
UNDERSTANDING THE UNIVERSE(LL)-W/CODE
Ch. 7.1 - Prob. 7.1CYUCh. 7.2 - Prob. 7.2CYUCh. 7.3 - Prob. 7.3CYUCh. 7.4 - Prob. 7.4CYUCh. 7.5 - Prob. 7.5CYUCh. 7 - Prob. 1QAPCh. 7 - Prob. 2QAPCh. 7 - Prob. 3QAPCh. 7 - Prob. 4QAPCh. 7 - Prob. 5QAP
Ch. 7 - Prob. 6QAPCh. 7 - Prob. 7QAPCh. 7 - Prob. 8QAPCh. 7 - Prob. 9QAPCh. 7 - Prob. 10QAPCh. 7 - Prob. 11QAPCh. 7 - Prob. 12QAPCh. 7 - Prob. 13QAPCh. 7 - Prob. 14QAPCh. 7 - Prob. 15QAPCh. 7 - Prob. 16QAPCh. 7 - Prob. 17QAPCh. 7 - Prob. 18QAPCh. 7 - Prob. 19QAPCh. 7 - Prob. 20QAPCh. 7 - Prob. 21QAPCh. 7 - Prob. 22QAPCh. 7 - Prob. 23QAPCh. 7 - Prob. 24QAPCh. 7 - Prob. 25QAPCh. 7 - Prob. 26QAPCh. 7 - Prob. 27QAPCh. 7 - Prob. 28QAPCh. 7 - Prob. 29QAPCh. 7 - Prob. 30QAPCh. 7 - Prob. 31QAPCh. 7 - Prob. 32QAPCh. 7 - Prob. 33QAPCh. 7 - Prob. 34QAPCh. 7 - Prob. 35QAPCh. 7 - Prob. 36QAPCh. 7 - Prob. 37QAPCh. 7 - Prob. 38QAPCh. 7 - Prob. 39QAPCh. 7 - Prob. 40QAPCh. 7 - Prob. 41QAPCh. 7 - Prob. 42QAPCh. 7 - Prob. 43QAPCh. 7 - Prob. 44QAPCh. 7 - Prob. 45QAP
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- The solar insolation at the top of the atmosphere is about 342 W/m^2. The total radiation absorbed at the surface of the Earth is 494 W/m^2. Explain how it is possible to absorb more radiation at the surface than comes in at the top of the atmosphere. (Answer should be one paragraph long)arrow_forwardWhat is a dust devil? Would you expect to feel more of a breeze from a dust devil on Mars or on Earth? Explain.arrow_forwardOne of our neighbours, Mars, has an average solar constant of SM = 589 Wm−2, an albedoof AM 0.24, and a surface temperature of -46◦C. What would its atmospheric emissivity, ϵM,need to be to achieve that surface temperature?arrow_forward
- Question 2: Planet Mars Planetary Attribute Albedo Radius Gravitational acceleration Mean distance from sun Surface pressure Symbol a R (km) g (m/s²) D (km) Po (kPa) Earth 0.29 6378 9.8 150 x 106 101 Mars 0.25 3395 3.7 228 x 106 0.6 (a) Calculate an appropriate value for shortwave solar radiation (SM) incident at the top of the Martian atmosphere (answer in W/m²). The corresponding value for Earth, SE = 1360 W/m². (b) Estimate the average surface temperature on Mars (answer in degrees Kelvin) using a suitable radiative energy balance. The greenhouse effect can be neglected for Mars. (c) Estimate the mass of the Martian atmosphere (answer in kg).arrow_forwardIn the graph from the class handout the inflow of energy from the sun is given as a constant 236 watts per meter squared. To get this figure we used L(1 – a) × 236 W/m², where L = 1350 W/m²is the solar constant, and a = 0.3 is the Earth's albedo (meaning that 30% of the Sun's energy is reflected back into space). The 1/4 comes from averaging the arriving solar energy over the whole Earth (the surface area of the Earth is 4 times the area of the "disk of energy" hitting the Earth.) Using these ideas estimate the inflow of energy to a planet if the solar constant is 647 watts per meter squared and the planet's albedo is 0.5. Round your answer to the near 10 watts per square meter.arrow_forward1arrow_forward
- Use the heuristic that a planet will have lost a given molecule from its atmosphere of 4.5 Billion years if the average molecular speed exceeds % of the planet's escape speed to calculate what mercury's mass would have to be in order to it to still have a nitrogen atmosphere like earth's? The molecular weight of nitrogen is 28 atomic units.arrow_forward___ nmarrow_forwardThe fraction of the energy flux received which is reflected into space is the albedo of Venus, av, which is about 0.76. The fraction of the energy flux which is absorbed is then (1-av) = 1. - 0.76 = 0.24. So the amount of energy actually absorbed by Venus in each second is Lv = (1-av)Ev. Lv = (1-av)Ev = ___________________ ergs/s And next calculate the effective temperature of Venus: Tv4 = (Lv/(4pdv2))/s = Lv/(4spdv2) = __________________ K4 and taking the square root of Tv4 twice in succession we get the effective Temperature Tv: Tv = [Lv/(4spdv2)]0.25 = _________________ K Calculate Venus' emittance assuming that the Venus' actual temperature, Tvr, is 472o C = 745 K: ev = Lv/(4pdv2s Tvr4) = __________________ .arrow_forward
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