Concept explainers
(a)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans
(b)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.
(c)
Interpretation:
The reagent used for the synthesis of the given compound should be determined.
Concept Introduction:
Deprotonation: The reaction in which proton is removed from the compound using reagents is known as deprotonation.
Different reagents are used for the deprotonation and one of the common reagent is sodium amide.
Lindlar catalyst: The catalyst is used for the hydrogenation of alkynes in a syn manner. This means both hydrogen are added on the same side across the triple bond and the product obtained will be a cis product.
Sodium in liquid ammonia: The catalyst is used for the formation of trans alkenes from alkynes. Because of its more reactivity towards triple bonds, the reaction will stop at the formation of alkenes.
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Chapter 7 Solutions
Student's Study Guide and Solutions Manual for Organic Chemistry
- Predict the major products of this reaction: ་ ་ + H NaOH ? Δ excess Note that the second reactant is used in excess, that is, there is much more of the second reactant than the first. If there won't be any products, just check the box under the drawing area instead.arrow_forwardP A student claims the right-hand side of the reaction in the drawing area below shows the product of a Claisen condensation. • If the student is correct, complete the reaction by adding the necessary organic reactants to the left-hand side, and by adding any necessary reagents and reaction conditions above and below the arrow. • If the student is incorrect, because it's not possible to obtain this product from a Claisen condensation, check the box under the drawing area instead. those that will minimize any byproducts or competing • Note for advanced students: If you have a choice, use the most efficient reactants and reagents reactions. - ☐ ☐ : ☐ + I Х Click and drag to start drawing a structure.arrow_forwardidentify the relationship between the structures and H- OH HO H H- OH and HO H H -ОН HO H Br and Brarrow_forward
- The right-hand side of this reaction shows the product of an aldol condensation. What are the reactants missing from the left-hand side? Draw them below. ? NaOH Δ If there aren't any reactants that would lead to these products under the reaction conditions given, just check the box under the drawing area. Note for advanced students: don't worry if the reactants you propose might also make some other products under these reaction conditions. Just make sure the product above is one of the major products.arrow_forwardPlease help! I need to identify four labeled unknown bottles based off of their colors doing titration using phenlphtalein. I've included my answers, but I wanted to make sure they were correct and if not, what will be correct thank you in advance.arrow_forwardAn organic chemistry Teaching Assistant (TA) suggested in your last discussion section that there is only one major organic product of the following reaction and that this reaction builds a ring. If the TA is right, draw the product in the drawing area below. If the TA is wrong, just check the box below the drawing area. NaOH ?arrow_forward
- A student suggests that the molecule on the right can be made from a single molecule that doesn't have a ring. If the student is correct, draw the starting material below, otherwise, check the box under the drawing area. Click and drag to start drawing a structure. : ☐ + NaOH टेarrow_forwardRate = k [I]1.7303[S2O82-]0.8502, Based on your rate, write down a mechanism consistent with your results and indicate which step is the rate determining step.arrow_forward36. Give the major product(s) of each of the following reactions. Aqueous work-up steps (when necessary) have been omitted. a. CH3CH=CHCH3 b. CH3CH2CH2CCH3 H,PO₂, H₂O, A (Hint: See Section 2-2.) 1. LIAIH. (CH,CH,),O 2. H', H₂O H NaBH, CH,CH₂OH d. Br LIAIH. (CH,CH,)₂O f. CH3 NaBH, CH,CH,OH (CH3)2CH H NaBH, CH,CH₂OH Harrow_forward
Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning