The following substances undergo complete combustion in a bomb calorimeter. The calorimeter assembly has a heat capacity of 5.136 kJ/°C.In each case, what is the final temperature if the initial water temperature is 22.43 °C? a. 0.3268 g caffeine, C 4 H 10 O 2 N 4 (heat of combustion = -1014.2 kcal/mol caffeine); b. 1.35 mL of methyl ethyl ketone , C 4 H 5 O ( I ) , d = 0.805 g / m L (heat of combustion = -2444 kJ/moI methyl ethyl ketone).
The following substances undergo complete combustion in a bomb calorimeter. The calorimeter assembly has a heat capacity of 5.136 kJ/°C.In each case, what is the final temperature if the initial water temperature is 22.43 °C? a. 0.3268 g caffeine, C 4 H 10 O 2 N 4 (heat of combustion = -1014.2 kcal/mol caffeine); b. 1.35 mL of methyl ethyl ketone , C 4 H 5 O ( I ) , d = 0.805 g / m L (heat of combustion = -2444 kJ/moI methyl ethyl ketone).
Solution Summary: The author explains that the final temperature of the solution in the calorimeter assembly is to be calculated when a particular amount of caffeine is combusted.
The following substances undergo complete combustion in a bomb calorimeter. The calorimeter assembly has a heat capacity of 5.136 kJ/°C.In each case, what is the final temperature if the initial water temperature is 22.43 °C? a. 0.3268 g caffeine,
C
4
H
10
O
2
N
4
(heat of combustion = -1014.2 kcal/mol caffeine); b. 1.35 mL of methyl ethyl ketone,
C
4
H
5
O
(
I
)
,
d
=
0.805
g
/
m
L
(heat of combustion = -2444 kJ/moI methyl ethyl ketone).
Definition Definition Organic compounds that have a carbonyl group, C = O, as their functional group. The carbonyl group in ketones is placed somewhere in the middle of the molecular structure, which means, the C=O is attached to two alkyl groups or benzene rings. Just like all other homologous series, the naming of ketones is done using a common suffix “-one”. The general molecular formula is C n H 2n O. Functional group of a ketone
1A
H 2A
Li Be
Use the References to access important values if needed for this question.
8A
3A 4A 5A 6A 7A He
B C N O F Ne
Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P
1B 2B Al Si
P S Cl Ar
K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr
Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe
*
Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn
Fr Ra Ac Rf Ha
******
Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu
Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr
Analyze the following reaction by looking at the electron configurations given below each box.
Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion.
Use the smallest integers possible.
cation
anion
+
+
Shell 1: 2
Shell 2: 8
Shell 3: 1
Shell 1 : 2
Shell 2 : 6
Shell 1 : 2
Shell 2: 8
Shell 1: 2
Shell 2: 8
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