In Fig. 7-10 a , a block of mass m lies on a horizontal frictionless surface and is attached to one end of a horizontal spring (spring constant k ) whose other end is fixed.The block is initially at rest at the position where the spring is unstretched ( x = 0 ) when a constant horizontal force F → in the positive direction of the x axis is applied to it. A plot of the resulting kinetic energy of the block versus its position x is shown in Fig. 7-36. The scale of the figure’s vertical axis is set by K s = 4.0 J. (a) What is the magnitude of F → ? (b) What is the value of k ? Figure 7-36 Problem 30.
In Fig. 7-10 a , a block of mass m lies on a horizontal frictionless surface and is attached to one end of a horizontal spring (spring constant k ) whose other end is fixed.The block is initially at rest at the position where the spring is unstretched ( x = 0 ) when a constant horizontal force F → in the positive direction of the x axis is applied to it. A plot of the resulting kinetic energy of the block versus its position x is shown in Fig. 7-36. The scale of the figure’s vertical axis is set by K s = 4.0 J. (a) What is the magnitude of F → ? (b) What is the value of k ? Figure 7-36 Problem 30.
In Fig. 7-10a, a block of mass m lies on a horizontal frictionless surface and is attached to one end of a horizontal spring (spring constant k) whose other end is fixed.The block is initially at rest at the position where the spring is unstretched (x= 0) when a constant horizontal force
F
→
in the positive direction of the x axis is applied to it. A plot of the resulting kinetic energy of the block versus its position x is shown in Fig. 7-36. The scale of the figure’s vertical axis is set by Ks = 4.0 J. (a) What is the magnitude of
F
→
? (b) What is the value of k?
1. A charge of -25 μC is distributed uniformly throughout a spherical volume of radius 11.5 cm.
Determine the electric field due to this charge at a distance of (a) 2 cm, (b) 4.6 cm, and (c) 25 cm from
the center of the sphere.
(a) =
=
(b) E =
(c)Ẻ =
=
NC NC NC
1.
A long silver rod of radius 3.5 cm has a charge of -3.9
ис
on its surface. Here ŕ is a unit vector
ст
directed perpendicularly away from the axis of the rod as shown in the figure.
(a) Find the electric field at a point 5 cm from the center of the rod (an outside point).
E =
N
C
(b) Find the electric field at a point 1.8 cm from the center of the rod (an inside point)
E=0
Think & Prepare
N
C
1. Is there a symmetry in the charge distribution? What kind of symmetry?
2. The problem gives the charge per unit length 1. How do you figure out the surface charge density σ
from a?
1. Determine the electric flux through each surface whose cross-section is shown below.
55
S₂
-29
S5
SA
S3
+ 9
Enter your answer in terms of q and ε
Φ
(a) s₁
(b) s₂
=
-29
(C) Φ
զ
Ερ
(d) SA
=
(e) $5
(f) Sa
$6
=
II
✓
-29
S6
+39
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.