Explanation Procedure used: Finding Inverse of a Square Matrix: 1. Form an augmented matrix [ A | I ] where a matrix A is placed along with a same dimension identity matrix I separated by a line. 2. Apply row operations on [ A | I ] in order to obtain another augmented matrix [ I | B ] where I is again an identity matrix and B is an inverse of A. 3. If the reduction process yields a row of zeros in the left half of the augmented matrix, then the inverse of A does not exist. Calculation: Consider the given matrix as A = [ 1 2 1 1 1 0 0 2 1 ] . First obtain the determinant of the matrix A to check whether the matrix A is invertible or not. The determinant of the matrix A is as follows. | A | = 1 [ 1 ⋅ 1 − 2 ⋅ 0 ] − 2 [ 1 ⋅ 1 − 0 ⋅ 0 ] + 1 [ 2 ⋅ 1 − 0 ⋅ 1 ] = 1 − 2 + 2 = 1 Since, the determinant | A | ≠ 0 ; the matrix A is nonsingular and invertible. Now, use the method of finding inverse of the matrix and obtain A − 1 as follows. The augment matrix [ A | I ] is [ A | I ] = [ 1 2 1 1 0 0 1 1 0 0 1 0 0 2 1 0 0 1 ] . Perform the row operations R 2 − R 1 → R 2 , and obtain the row reduced equivalent matrix as, [ 1 2 1 1 0 0 0 − 1 − 1 − 1 1 0 0 2 1 0 0 1 ] Perform the row operations R 3 + 2 R 2 → R 3 and obtain the equivalent row reduced matrix as, [ 1 2 1 1 0 0 0 − 1 − 1 − 1 1 0 0 0 − 1 − 2 2 1 ] Perform the row operation ( 1 − 1 ) R 3 → R 3 and obtain the equivalent row reduced matrix as,

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Chapter 7, Problem 23RE

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To find: The inverse of the matrix [121110021].

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Chapter 7, Problem 22RE

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Chapter 7 Solutions

EBK COLLEGE ALGEBRA IN CONTEXT

Ch. 7.1 - In Exercises 14, solve the systems of equations....Ch. 7.1 - Prob. 2E Ch. 7.1 - Prob. 3E Ch. 7.1 - Prob. 4E Ch. 7.1 - Prob. 5E Ch. 7.1 - Prob. 6E Ch. 7.1 - Prob. 7E Ch. 7.1 - Prob. 8E Ch. 7.1 - Prob. 9E Ch. 7.1 - Prob. 10E

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The inverse of the matrix [ 1 2 1 1 1 0 0 2 1 ] .

Solution Summary: The author explains how to find the inverse of a square matrix.

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To find: The inverse of the matrix [121110021].

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