Loose Leaf for Statistical Techniques in Business and Economics
17th Edition
ISBN: 9781260152647
Author: Douglas A. Lind
Publisher: McGraw-Hill Education
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Chapter 7, Problem 2.3PT
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Find the possible number of ways in which the cars belonging to the CPAs can be arranged in the five spots.
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3. [15] The joint PDF of RVS X and Y is given by
fx.x(x,y) = {
x) = { c(x +
{
c(x+y³),
0,
0≤x≤ 1,0≤ y ≤1
otherwise
where c is a constant.
(a) Find the value of c.
(b) Find P(0 ≤ X ≤,
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7. [10] Suppose that Xi, i = 1,..., 5, are independent normal random variables, where
X1, X2 and X3 have the same distribution N(1, 2) and X4 and X5 have the same
distribution N(-1, 1). Let
(a) Find V(X5 - X3).
1
= √(x1 + x2) — — (Xx3 + x4 + X5).
(b) Find the distribution of Y.
(c) Find Cov(X2 - X1, Y).
-
Chapter 7 Solutions
Loose Leaf for Statistical Techniques in Business and Economics
Ch. 7 - Microwave ovens only last so long. The life-time...Ch. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 2SRCh. 7 - The distribution of the annual incomes of a group...Ch. 7 - Explain what is meant by this statement: There is...
Ch. 7 - List the major characteristics of a normal...Ch. 7 - The mean of a normal probability distribution is...Ch. 7 - The mean of a normal probability distribution is...Ch. 7 - The Kamp family has twins, Rob and Rachel. Both...Ch. 7 - Prob. 12ECh. 7 - The temperature of coffee sold at the Coffee Bean...Ch. 7 - A normal population has a mean of 20.0 and a...Ch. 7 - A normal population has a mean of 12.2 and a...Ch. 7 - A recent study of the hourly wages of maintenance...Ch. 7 - The mean of a normal probability distribution is...Ch. 7 - Prob. 5SRCh. 7 - Prob. 17ECh. 7 - A normal population has a mean of 80.0 and a...Ch. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - WNAE, an all-news AM station, finds that the...Ch. 7 - Prob. 22ECh. 7 - Prob. 6SRCh. 7 - A normal distribution has a mean of 50 and a...Ch. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 7SRCh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 8SRCh. 7 - Prob. 37ECh. 7 - The lifetime of LCD TV sets follows an exponential...Ch. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41CECh. 7 - Prob. 42CECh. 7 - Prob. 43CECh. 7 - Prob. 44CECh. 7 - Prob. 45CECh. 7 - Prob. 46CECh. 7 - Prob. 47CECh. 7 - Prob. 48CECh. 7 - Shaver Manufacturing Inc. offers dental insurance...Ch. 7 - The annual commissions earned by sales...Ch. 7 - Prob. 51CECh. 7 - Prob. 52CECh. 7 - Management at Gordon Electronics is considering...Ch. 7 - Fast Service Truck Lines uses the Ford Super Duty...Ch. 7 - Prob. 55CECh. 7 - Prob. 56CECh. 7 - Prob. 57CECh. 7 - Prob. 58CECh. 7 - Prob. 59CECh. 7 - Prob. 60CECh. 7 - Prob. 61CECh. 7 - Prob. 62CECh. 7 - The weights of canned hams processed at Henline...Ch. 7 - Prob. 64CECh. 7 - Prob. 65CECh. 7 - The price of shares of Bank of Florida at the end...Ch. 7 - Prob. 67CECh. 7 - Prob. 68CECh. 7 - Prob. 69CECh. 7 - Prob. 70CECh. 7 - Prob. 71CECh. 7 - Prob. 72CECh. 7 - Prob. 73CECh. 7 - Prob. 1PCh. 7 - Prob. 2PCh. 7 - Prob. 3PCh. 7 - Prob. 4PCh. 7 - Prob. 5PCh. 7 - Prob. 6PCh. 7 - Prob. 1.1PTCh. 7 - Prob. 1.2PTCh. 7 - Prob. 1.3PTCh. 7 - Prob. 1.4PTCh. 7 - Prob. 1.5PTCh. 7 - Prob. 1.6PTCh. 7 - Which of the following is NOT a requirement of the...Ch. 7 - Prob. 1.8PTCh. 7 - How many standard normal distributions are there?...Ch. 7 - Prob. 1.10PTCh. 7 - Prob. 1.11PTCh. 7 - Prob. 1.12PTCh. 7 - Prob. 1.13PTCh. 7 - Prob. 1.14PTCh. 7 - Prob. 1.15PTCh. 7 - Prob. 2.1PTCh. 7 - Prob. 2.2PTCh. 7 - Prob. 2.3PTCh. 7 - Prob. 2.4PTCh. 7 - Prob. 2.5PTCh. 7 - Prob. 2.6PTCh. 7 - Prob. 2.7PT
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- 1. [10] Suppose that X ~N(-2, 4). Let Y = 3X-1. (a) Find the distribution of Y. Show your work. (b) Find P(-8< Y < 15) by using the CDF, (2), of the standard normal distribu- tion. (c) Find the 0.05th right-tail percentage point (i.e., the 0.95th quantile) of the distri- bution of Y.arrow_forward6. [10] Let X, Y and Z be random variables. Suppose that E(X) = E(Y) = 1, E(Z) = 2, V(X) = 1, V(Y) = V(Z) = 4, Cov(X,Y) = -1, Cov(X, Z) = 0.5, and Cov(Y, Z) = -2. 2 (a) Find V(XY+2Z). (b) Find Cov(-x+2Y+Z, -Y-2Z).arrow_forward1. [10] Suppose that X ~N(-2, 4). Let Y = 3X-1. (a) Find the distribution of Y. Show your work. (b) Find P(-8< Y < 15) by using the CDF, (2), of the standard normal distribu- tion. (c) Find the 0.05th right-tail percentage point (i.e., the 0.95th quantile) of the distri- bution of Y.arrow_forward
- == 4. [10] Let X be a RV. Suppose that E[X(X-1)] = 3 and E(X) = 2. (a) Find E[(4-2X)²]. (b) Find V(-3x+1).arrow_forward2. [15] Let X and Y be two discrete RVs whose joint PMF is given by the following table: y Px,y(x, y) -1 1 3 0 0.1 0.04 0.02 I 2 0.08 0.2 0.06 4 0.06 0.14 0.30 (a) Find P(X ≥ 2, Y < 1). (b) Find P(X ≤Y - 1). (c) Find the marginal PMFs of X and Y. (d) Are X and Y independent? Explain (e) Find E(XY) and Cov(X, Y).arrow_forward32. Consider a normally distributed population with mean μ = 80 and standard deviation σ = 14. a. Construct the centerline and the upper and lower control limits for the chart if samples of size 5 are used. b. Repeat the analysis with samples of size 10. 2080 101 c. Discuss the effect of the sample size on the control limits.arrow_forward
- Consider the following hypothesis test. The following results are for two independent samples taken from the two populations. Sample 1 Sample 2 n 1 = 80 n 2 = 70 x 1 = 104 x 2 = 106 σ 1 = 8.4 σ 2 = 7.6 What is the value of the test statistic? If required enter negative values as negative numbers (to 2 decimals). What is the p-value (to 4 decimals)? Use z-table. With = .05, what is your hypothesis testing conclusion?arrow_forwardPeriodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating. Consultant A Consultant B = 16 = 10 = 6.82 = 6.25 = .64 = .75 State the null and alternative hypotheses.H0: 1 - 2 Ha: 1 - 2 Compute the value of the test statistic (to 2 decimals). What is the p-value?The p-value is What is your conclusion?arrow_forwardA firm paid its first annual dividend yesterday in the amount of $.15 per share. The company plans to double the dividend in each of the next 3 years. Starting in Year 4, the firm plans to pay $1.50 per share indefinitely. What is one share of this stock worth today if the market rate of return on similar securities is 13.8 percent? Multiple Choice $11.79 $8.92 $10.77 $11.02 $10.26arrow_forward
- Suppose the random variable X is normally distributed with mean 80 and standard deviation 16. Find following probabilities. Find ‘b’ such that P(X ≥ b) = 0.975. Find the probability using a normal distribution table AND using ti-83 calculator. SHOW ALL STEPS PLEASE.arrow_forwardSuppose the random variable X is normally distributed with mean 80 and standard deviation 16. Find following probabilities. Equation: P(85 ≤ X ≤ 102). Find the probability using a normal distribution table AND using ti-83 calculator. SHOW ALL STEPS PLEASE.arrow_forwardData set is Bachelor Degree's Conferred by Race and Ethnicity.arrow_forward
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