Explain why small-angle grain boundaries are not as effective in interfering with the slip process as are high angle grain boundaries.

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#3 Using the initial rates method and the given experimental data below to determine the rate law and the value of the rate constant for the reaction, as shown below. All trials are performed at the same temperature. 2NO + Cl2 → 2NCOCI Trial [NO] (mol/L) [Cl₂] (mol/L) Initial rates (mol/L.s) 1 0.10 0.10 0.00300 2 0.10 0.15 0.00450 3 0.15 0.10 0.00675

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Chapter 7, Problem 20QAP

To determine

Explain why small-angle grain boundaries are not as effective in interfering with the slip process as are high angle grain boundaries.

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#3 Using the initial rates method and the given experimental data below to determine the rate law and the value of the rate constant for the reaction, as shown below. All trials are performed at the same temperature. 2NO + Cl2 → 2NCOCI Trial [NO] (mol/L) [Cl₂] (mol/L) Initial rates (mol/L.s) 1 0.10 0.10 0.00300 2 0.10 0.15 0.00450 3 0.15 0.10 0.00675

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