Chapter 7, Problem 1P

7-11 Consider the following reaction:

Suppose we start the reaction with an initial iodomethane concentration of 0.260 M. This concentration increases to 0.840 M over a period of 1 h 20 min. What is the rate of reaction?

Interpretation Introduction

Interpretation:

The rate of given reaction with initial concentration of iodomethane0.26 m and increased to 0.84 m in 1 h 20 min should be determined.

Concept Introduction:

Rate of reaction:

The rate of any reaction depends on the concentration change of limiting reagent formed in a reaction.

Concentration:

Concentration of all chemical species takes part in a reaction depend on their moles present in per liter solution.

$\mathrm{Rate}=\frac{\mathrm{Final}\text{ concentration}-\text{initial concentration}}{\text{change in time}}$.

Answer to Problem 1P

Rate of reaction = 0.00725 M/min.

Explanation of Solution

Given information:

Reaction with initial concentration of iodomethane 0.26 m that increased to 0.84 m in 1 h 20 min.

$\mathrm{Rate}=\frac{\mathrm{Final}\text{ concentration}-\text{initial concentration}}{\text{change in time}}$

Put the given values in above expression.

$\text{Rate=}\frac{\text{0}\text{.84-0}\text{.26}}{\text{80}}\text{=}\frac{\text{0}\text{.58}}{\text{80}}\text{=0}\text{.00725 M/min}$.

Conclusion

Rate of reaction = 0.00725 M/min.