
Concept explainers
The following is a list of mutational changes. For each of the specific mutations described, indicate which of the terms in the right-hand column applies, either as a description of the mutation or as a possible cause. More than one term from the right column can apply to each statement in the left column.
1. an A-T base pair in the wild-type gene is changed to a G-C pair | a. transition |
2. an A-T base pair is changed to a T-A pair | b. base substitution |
3. the sequence AAGCTTATCG is changed to AAGCTATCG | c. transversion |
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG | d. deletion |
5. the sequence AACGTTATCG is changed to AATGTTATCG | e. insertion |
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG | f. deamination |
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG | g. X-ray irradiation |
h. intercalator | |
i. slipped mispairing |

1.
To determine:
The item that describes “an A-T base pair in the wild-type gene is changed to a G-C pair.”
1. an A-T base pair in the wild-type gene is changed to a G-C pair.
2. an A-T base pair is changed to a T-A pair.
3. the sequence AAGCTTATCG is changed to AAGCTATCG.
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG.
5. the sequence AACGTTATCG is changed to AATGTTATCG.
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG.
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG.
Introduction:
When purines and pyrimidines are exchanged with each other, the process is called transition.
Answer to Problem 1P
Correct answer:
An A-T base pair in the wild-type gene is changed to a G-C pair: transition and base substitution.
Explanation of Solution
In the given mutation, A-T base pair is exchanged with a G-C base pair so it can be a base substitution. This can also be a transition mutation because adenine is a purine which is interchanged with another purine that is guanine. Thymine replaced the cytosine, and both are also pyrimidines. Thus, this condition can be a base substitution mutation or a transition mutation.

2.
To determine:
The item that describes “an A-T base pair is changed to a T-A pair”.
1. an A-T base pair in the wild-type gene is changed to a G-C pair.
2. an A-T base pair is changed to a T-A pair.
3. the sequence AAGCTTATCG is changed to AAGCTATCG.
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG.
5. the sequence AACGTTATCG is changed to AATGTTATCG.
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG.
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG.
Introduction:
When one purine is replaced by pyrimidine in a pair of two bases, the resulting process is called transversion.
Answer to Problem 1P
Correct answer:
an A-T base pair is changed to a T-A pair: base substitution and transversion.
Explanation of Solution
In the given mutation, a base pair ‘A-T’ can be changed to a ‘T-A’ base-pair so the replacement of one purine with pyrimidine can be observed. Thus, the mutation for concerting A-T into T-A can be a transversion. The substitution of A by T is taking place so, it can also be a base substitution mutation.

3.
To determine:
The item that describes “the sequence AAGCTTATCG is changed to AAGCTATCG”.
1. an A-T base pair in the wild-type gene is changed to a G-C pair.
2. an A-T base pair is changed to a T-A pair.
3. the sequence AAGCTTATCG is changed to AAGCTATCG.
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG.
5. the sequence AACGTTATCG is changed to AATGTTATCG.
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG.
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG.
Introduction:
In this particular case, the exposure of X-rays is responsible for deletion mutation from the wild type sequence.
Answer to Problem 1P
Correct answer:
the sequence AAGCTTATCG is changed to AAGCTATCG: deletion and X-ray irradiation.
Explanation of Solution
If both, wild type and mutated sequence are observed that it can be seen that there is a deletion of nitrogenous base T from wild type sequence. The exposure to X-ray irradiation may be responsible for deletion mutation. Thus, the correct match for the given mutation is deletion and X-ray irradiation.

4.
To determine:
The item that describes “the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG”.
1. an A-T base pair in the wild-type gene is changed to a G-C pair.
2. an A-T base pair is changed to a T-A pair.
3. the sequence AAGCTTATCG is changed to AAGCTATCG.
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG.
5. the sequence AACGTTATCG is changed to AATGTTATCG.
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG.
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG.
Introduction:
When one or more nitrogenous bases are added to a specific sequence of nucleotides, then the process of insertion takes place.
Answer to Problem 1P
Correct answer:
The sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG: insertion and intercalator.
Explanation of Solution
Insertion is a mutation in which a nitrogenous base or a group of the nitrogenous bases are added to a sequence. In the given mutation, a thymine residue is added to the wild type sequence for mutation. Thus, the kind of mutation is an insertion, and it can result from the introduction of some chemical mutagens like ethidium bromide. These chemical mutagens are intercalated with sequence and are known as intercalators. Thus, the correct match for the given mutation is insertion and intercalator.

5.
To determine:
The item that describes “the sequence AACGTTATCG is changed to AATGTTATCG”.
1. an A-T base pair in the wild-type gene is changed to a G-C pair.
2. an A-T base pair is changed to a T-A pair.
3. the sequence AAGCTTATCG is changed to AAGCTATCG.
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG.
5. the sequence AACGTTATCG is changed to AATGTTATCG.
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG.
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG.
Introduction:
Transition is the change of one purine to another purine or one pyrimidine to another pyrimidine.
Answer to Problem 1P
Correct answer:
the sequence AACGTTATCG is changed to AATGTTATCG: base substitution, transition, and deamination.
Explanation of Solution
In the given mutation, base T is exchanged with base C so it can be a base substitution. This can also be a transition mutation because cytosine is a pyrimidine which is interchanged with another pyrimidine that is thymine. Deamination can also be noticed in the given mutation because the conversion of a methylated C to T is taking place. Thus, the correct match for the given mutation is a substitution, transition, and deamination.

6.
To determine:
The item that describes “the sequence AACGTCACACACATCG is changed to AACGTCACATCG”.
1. an A-T base pair in the wild-type gene is changed to a G-C pair.
2. an A-T base pair is changed to a T-A pair.
3. the sequence AAGCTTATCG is changed to AAGCTATCG.
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG.
5. the sequence AACGTTATCG is changed to AATGTTATCG.
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG.
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG.
Introduction:
Crossing over is the process of exchange of genetic material between the sister chromatids at chiasmata.
Answer to Problem 1P
Correct answer:
The sequence AACGTCACACACATCG is changed to AACGTCACATCG: deletion and crossing over.
Explanation of Solution
In the given mutation, it can be noticed that a segment CACACACA has been lost from wild type sequence, so it is representing deletion. A segment can be removed from the wild type gene during the process of crossing over. Thus, the correct match for the given mutation is deletion and crossing over.

7.
To determine:
The item that describes “the sequence AAGCTTATCG is changed to AAGCTTTATCG”.
1. an A-T base pair in the wild-type gene is changed to a G-C pair.
2. an A-T base pair is changed to a T-A pair.
3. the sequence AAGCTTATCG is changed to AAGCTATCG.
4. the sequence CAGCAGCAGCAGCAGCAG is changed to CAGCAGCAGCAGCAGCAGCAG.
5. the sequence AACGTTATCG is changed to AATGTTATCG.
6. the sequence AACGTCACACACATCG is changed to AACGTCACATCG.
7. the sequence AAGCTTATCG is changed to AAGCTTTATCG.
Introduction:
When one or more nitrogenous bases are removed from the nucleotide sequence, then the process is called deletion.
Answer to Problem 1P
Correct answer:
the sequence AAGCTTATCG is changed to AAGCTTTATCG: deletion and X-ray irradiation.
Explanation of Solution
Observation of wild type and mutated sequence can lead to a conclusion that there is a deletion of nitrogenous base T from wild type sequence. Deletion mutation may happen to because of exposure to X-ray irradiation. Thus, the correct match for the given mutation is deletion and X-ray irradiation.
Want to see more full solutions like this?
Chapter 7 Solutions
Genetics: From Genes to Genomes
Additional Science Textbook Solutions
Campbell Essential Biology (7th Edition)
Organic Chemistry
Microbiology Fundamentals: A Clinical Approach
Human Physiology: An Integrated Approach (8th Edition)
Laboratory Manual For Human Anatomy & Physiology
- Skryf n kortkuns van die Egyptians pyramids vertel ñ story. Maximum 500 woordearrow_forward1.)What cross will result in half homozygous dominant offspring and half heterozygous offspring? 2.) What cross will result in all heterozygous offspring?arrow_forward1.Steroids like testosterone and estrogen are nonpolar and large (~18 carbons). Steroids diffuse through membranes without transporters. Compare and contrast the remaining substances and circle the three substances that can diffuse through a membrane the fastest, without a transporter. Put a square around the other substance that can also diffuse through a membrane (1000x slower but also without a transporter). Molecule Steroid H+ CO₂ Glucose (C6H12O6) H₂O Na+ N₂ Size (Small/Big) Big Nonpolar/Polar/ Nonpolar lonizedarrow_forward
- what are the answer from the bookarrow_forwardwhat is lung cancer why plants removes liquid water intead water vapoursarrow_forward*Example 2: Tracing the path of an autosomal dominant trait Trait: Neurofibromatosis Forms of the trait: The dominant form is neurofibromatosis, caused by the production of an abnormal form of the protein neurofibromin. Affected individuals show spots of abnormal skin pigmentation and non-cancerous tumors that can interfere with the nervous system and cause blindness. Some tumors can convert to a cancerous form. i The recessive form is a normal protein - in other words, no neurofibromatosis.moovi A typical pedigree for a family that carries neurofibromatosis is shown below. Note that carriers are not indicated with half-colored shapes in this chart. Use the letter "N" to indicate the dominant neurofibromatosis allele, and the letter "n" for the normal allele. Nn nn nn 2 nn Nn A 3 N-arrow_forward
- I want to be a super nutrition guy what u guys like recommend mearrow_forwardPlease finish the chart at the bottom. Some of the answers have been filled in.arrow_forward9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. 18 carbons fatty acids 12 carbons 9 glycerol A. Glycerol is broken down to glyceraldehyde 3-phosphate, a glycolysis intermediate via the following pathway shown in the figure below. Notice this process costs one ATP but generates one FADH2. Continue generating ATP with glyceraldehyde-3-phosphate using the standard pathway and aerobic respiration. glycerol glycerol-3- phosphate…arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningBiology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage LearningBiology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning
- Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxHuman Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage LearningBiology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning





