Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
15th Edition
ISBN: 9781119231318
Author: Morris Hein
Publisher: Wiley (WileyPLUS Products)
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Chapter 7, Problem 18PE
(a)
Interpretation Introduction
Interpretation:
The
(b)
Interpretation Introduction
Interpretation:
The number of mole has to be converted into kilogram.
(c)
Interpretation Introduction
Interpretation:
The molecules of sulfur dioxide have to be converted into grams.
(d)
Interpretation Introduction
Interpretation:
The moles of
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6. The equilibrium constant for the reaction
2 HBr (g)
→ H2(g) + Br2(g)
Can be expressed by the empirical formula
11790 K
In K-6.375 + 0.6415 In(T K-¹)
-
T
Use this formula to determine A,H as a function of temperature. Calculate A,-H at 25 °C and at
100 °C.
3. Nitrosyl chloride, NOCI, decomposes according to
2 NOCI (g) → 2 NO(g)
+ Cl2(g)
Assuming that we start with no moles of NOCl (g) and no NO(g) or Cl2(g), derive an expression
for Kp in terms of the equilibrium value of the extent of reaction, Seq, and the pressure, P.
Given that K₂ = 2.00 × 10-4, calculate Seq/
of
29/no when P = 0.080 bar. What is the new value
по
ƒª/ at equilibrium when P = 0.160 bar? Is this result in accord with Le Châtelier's
Principle?
Consider the following chemical equilibrium:
2SO2(g) + O2(g) = 2SO3(g)
•
Write the equilibrium constant expression for this reaction.
Now compare it to the equilibrium constant expression for the related reaction:
•
.
1
SO2(g) + O2(g) = SO3(g)
2
How do these two equilibrium expressions differ?
What important principle about the dependence of equilibrium constants on the stoichiometry of a
reaction can you learn from this comparison?
Chapter 7 Solutions
Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
Ch. 7.1 - Prob. 7.1PCh. 7.1 - Prob. 7.2PCh. 7.1 - Prob. 7.3PCh. 7.2 - Prob. 7.4PCh. 7.2 - Prob. 7.5PCh. 7.2 - Prob. 7.6PCh. 7.3 - Prob. 7.7PCh. 7.3 - Prob. 7.8PCh. 7.3 - Prob. 7.9PCh. 7.4 - Prob. 7.10P
Ch. 7.4 - Prob. 7.11PCh. 7.5 - Prob. 7.12PCh. 7 - Prob. 1RQCh. 7 - Prob. 2RQCh. 7 - Prob. 3RQCh. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQCh. 7 - Prob. 11RQCh. 7 - Prob. 12RQCh. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 17RQCh. 7 - Prob. 18RQCh. 7 - Prob. 19RQCh. 7 - Prob. 1PECh. 7 - Prob. 2PECh. 7 - Prob. 3PECh. 7 - Prob. 4PECh. 7 - Prob. 5PECh. 7 - Prob. 6PECh. 7 - Prob. 7PECh. 7 - Prob. 8PECh. 7 - Prob. 9PECh. 7 - Prob. 10PECh. 7 - Prob. 11PECh. 7 - Prob. 12PECh. 7 - Prob. 13PECh. 7 - Prob. 14PECh. 7 - Prob. 15PECh. 7 - Prob. 16PECh. 7 - Prob. 17PECh. 7 - Prob. 18PECh. 7 - Prob. 19PECh. 7 - Prob. 20PECh. 7 - Prob. 21PECh. 7 - Prob. 22PECh. 7 - Prob. 25PECh. 7 - Prob. 26PECh. 7 - Prob. 27PECh. 7 - Prob. 28PECh. 7 - Prob. 29PECh. 7 - Prob. 30PECh. 7 - Prob. 31PECh. 7 - Prob. 32PECh. 7 - Prob. 33PECh. 7 - Prob. 34PECh. 7 - Prob. 35PECh. 7 - Prob. 36PECh. 7 - Prob. 37PECh. 7 - Prob. 38PECh. 7 - Prob. 39PECh. 7 - Prob. 40PECh. 7 - Prob. 41PECh. 7 - Prob. 42PECh. 7 - Prob. 43PECh. 7 - Prob. 44PECh. 7 - Prob. 45PECh. 7 - Prob. 46PECh. 7 - Prob. 47PECh. 7 - Prob. 48PECh. 7 - Prob. 49PECh. 7 - Prob. 50PECh. 7 - Prob. 51PECh. 7 - Prob. 52PECh. 7 - Prob. 53AECh. 7 - Prob. 54AECh. 7 - Prob. 55AECh. 7 - Prob. 56AECh. 7 - Prob. 57AECh. 7 - Prob. 58AECh. 7 - Prob. 59AECh. 7 - Prob. 60AECh. 7 - Prob. 61AECh. 7 - Prob. 62AECh. 7 - Prob. 63AECh. 7 - Prob. 64AECh. 7 - Prob. 65AECh. 7 - Prob. 66AECh. 7 - Prob. 67AECh. 7 - Prob. 68AECh. 7 - Prob. 69AECh. 7 - Prob. 70AECh. 7 - Prob. 71AECh. 7 - Prob. 72AECh. 7 - Prob. 73AECh. 7 - Prob. 74AECh. 7 - Prob. 75AECh. 7 - Prob. 76AECh. 7 - Prob. 77AECh. 7 - Prob. 78AECh. 7 - Prob. 79AECh. 7 - Prob. 80AECh. 7 - Prob. 81AECh. 7 - Prob. 82AECh. 7 - Prob. 83AECh. 7 - Prob. 84AECh. 7 - Prob. 88AECh. 7 - Prob. 89CECh. 7 - Prob. 90CE
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- (3 pts) Use the Kapustinskii equation to calculate the lattice enthalpy for MgBr2 anddiscuss any differences between this result and that from #4.arrow_forward(3 pts) Silver metal adopts a fcc unit cell structure and has an atomic radius of 144 pm. Fromthis information, calculate the density of silver. Show all work.arrow_forward4. (3 pts) From the information below, determine the lattice enthalpy for MgBr2. Show all work. AH/(kJ mol-¹) Sublimation of Mg(s) +148 lonization of Mg(g) +2187 to Mg2+(g) Vaporization of Br₂(1) +31 Dissociation of Br,(g) +193 Electron gain by Br(g) -331 Formation of MgBr₂(s) -524arrow_forward
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