Chapter 7, Problem 150AE

(a)

Interpretation Introduction

Interpretation:

The pH of the $\text{1}{\text{.2 M CaBr}}_2$ solution should be calculated.

Concept Introduction :

The pH of the solution can be calculated using the following relation:

  $\text{pH = }-\log \left[{\text{H}}^{+}\right]$

Here, $\left[{\text{H}}^{+}\right]$ is the concentration of hydrogen ion concentration.

(b)

Interpretation Introduction

Interpretation:

The pH of the $\text{0}{\text{.84 M C}}_6{\text{H}}_5{\text{NH}}_3{\text{NO}}_3$ solution should be calculated.

Concept Introduction :

The pH of the solution can be calculated using the following relation:

  $\text{pH = }-\log \left[{\text{H}}^{+}\right]$

Here, $\left[{\text{H}}^{+}\right]$ is the concentration of hydrogen ion concentration.

(c)

Interpretation Introduction

Interpretation:

The pH of the $\text{0}{\text{.57 M KC}}_7{\text{H}}_5{\text{O}}_2$ solution should be calculated.

Concept Introduction :

The pH of the solution can be calculated using the following relation:

  $\text{pH = }-\log \left[{\text{H}}^{+}\right]$

Here, $\left[{\text{H}}^{+}\right]$ is the concentration of hydrogen ion concentration.