Path To College Mathematics
1st Edition
ISBN: 9780134654409
Author: Martin-Gay, K. Elayn, 1955-
Publisher: Pearson,
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Chapter 7, Problem 14CR
To determine
(a)
To determine if the given ordered pair is a solution to the given system.
To determine
(b)
To determine if the given ordered pair is a solution to the given system.
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The purpose of this problem is to solve the Black-Scholes PDE with analytical techniques,
which will lead us back to the Black-Scholes formula. The technique is very similar to the
one used with the Feynman-Kac formula back in MATH 467.
Let's consider the PDE given by
with terminal condition f(T,x)
af
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af
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- rf = 0,
=
(x-K)+. The solution f(t, x) corresponds to the price
of a call option (given the initial condition) at time t if the stock price is x.
(a) The first two things that prevent us from solving this PDE directly are
(i) the fact that we have a terminal condition, instead of an initial condition;
(ii) the terms in front of the derivatives are not constant.
To address these, we use the transformation g(t, x) = ƒ(T − t,e³), equivalent to
f(t, x) = g(T-t, log(x)). Under this condition, determine the PDE and the initial
condition satisfied by g.
(b) Now, the PDE obtained in (a) should have an initial condition and constant coeffi-
cients, but it still…
٣:٥٣
النموذج الاول
. . .
O O O
بشما ند الحمر الحمر
الجمهورية الجنية
وزارة التربية والتعليم
اليوم
التاريخ
اللجنة العليا للاختبارات
الزمن
اختبار مادة الجبر والهندسة
لجنة المطابع السرية المركزية
للشهادة الثانوية العامة (القسم العلمي)
الفترة
%97
(1)
ظلل في ورقة الإجابة الدائرة التي تحتوي على الحرف ( ص ) للإجابة الصحيحة والحرف ( خ ) للإجابة الخطأ بحسب رقم الفقرة لكل مما يأتي ( درجة لكل فقرة )
)1
)
2
)
3
)
4
) بؤرة القطع س" = ١٢ ص هي (
۲
) طول المحور الأصغر للقطع ٩ س + ص = ٩ يساوي 6 وحدات طول .
) إذا كان & عدد مركب ، 181 + 11 = ٦ ، فإن ١١ = ٣ .
) إذا كان م + ۳ ت = ۲ + ت ب م ، ب دع ، فإن م + ب =
5 ( ) إذا كان & = ۱ + ٣ ت ، فإن ٠ = ١٠ .
6 ( - ) إذا كان ٥٠ - ٣ - ١٢٠ ٤ - ٣ ، فإن قيمة ٧ = ٥ .
1
)
=
N
) إذا كان ح هو الحد الخالي من س في المفكوك ( س +
v. N
8 ( ( قيمة المقدار , = + ۱ ، * . . +
، فإن قيمة ٧ = ١٦ .
۱ +
9 ( ) المستقيمان المقاربان للقطع الذي معادلته س" = ١ هما ص = :
۹
10 ( ) إذا كان ٥ + س = ٢٤ ، فإن قيمة س = - 1
س
11 ( ) إذا كانت النسبة بين الحدين الأوسطين تساوي 9 في المفكوك ( س + - ) ،…
الاسم
يمنع استخدام الآلة الحاسبة
ظلل في ورقة الإجابة الدائرة التي تحتوي على الحرف (ص) للإجابة الصحيحة والحرف (خ) للإجابة الخطأ بحسب رقم الفقرة لكل مما يأتي:
درجة لكل فقرة.
( ) نها جا
元
جتا
= صفر
س ۱
س
س -۱
( ) يمكن إعادة تعريف الدالة د(س) = س قاس لكي تكون متصلة عند س = 7
( ) إذا كانت د(س) = (٢) س - س ) ؛ فإن د(١) = ٦
٢ س ص ( ) إذا كانت س +
0=
؛ فإن عند ) - ١ ، - ٦ ) تساوي (٦)
( ) إذا كانت د(س) = س ه ، و (س) = ٣ س ٢ + ٢ س ؛ فإن ( د ) (۱) = ۸
) ( معادلة ناظم الدالة ص = د(س) عند النقطة ) ( ، د (۲)) هي ص - (د (م) - - د (۲) ( س - م )
( ) إذا كانت ص = ظتا٢ س ؛ فإن ص = ٢ ص قتا ٢س
) ( إذا كانت د(س) = س ؛ فإن د (T) =
جتاس
1-
T
( ) إذا كانت د(س) = 1 - جناس
جاس
؛ فإن د () = - 1
( ) إذا كانت الدالة د (س) تحقق شروط مبرهنة القيمة المتوسطة على [ ، ب ] ، فإنه يوجد جـ ] ، ب [ بحيث (جـ) =
(P) + (~)- -
ب + P
1
2
3
4
5
6
7
8
9
10
11
( ) للدالة د(س) = لو ( س ) + (٣) نقطة حرجة عند س = .
( ) إذا كان س = - ٢ مقارباً رأسياً للدالة د(س)
12
10 13
14
15
16
17
س = لو|س | + ث
-
=
۲ س + ٣
ب س + ٤ ، فإن معادلة…
Chapter 7 Solutions
Path To College Mathematics
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Ch. 7.1 - Prob. 11ESCh. 7.1 - Prob. 12ESCh. 7.1 - Prob. 13ESCh. 7.1 - Prob. 14ESCh. 7.1 - Prob. 15ESCh. 7.1 - Prob. 16ESCh. 7.1 - Prob. 17ESCh. 7.1 - Prob. 18ESCh. 7.1 - Prob. 19ESCh. 7.1 - Suppose a 6-sided die is tossed twice. (This is a...Ch. 7.1 - Prob. 21ESCh. 7.1 - Prob. 22ESCh. 7.1 - Prob. 23ESCh. 7.1 - Prob. 24ESCh. 7.1 - Solve. Current license plates in California now...Ch. 7.1 - Prob. 26ESCh. 7.1 - Although there are exceptions, the call signs for...Ch. 7.1 - Prob. 28ESCh. 7.1 - Prob. 29ESCh. 7.1 - Prob. 30ESCh. 7.1 - Prob. 31ESCh. 7.1 - Prob. 32ESCh. 7.1 - Prob. 33ESCh. 7.1 - Prob. 34ESCh. 7.1 - Prob. 35ESCh. 7.1 - Prob. 36ESCh. 7.1 - Prob. 37ESCh. 7.1 - Prob. 38ESCh. 7.1 - Prob. 39ESCh. 7.1 - Prob. 40ESCh. 7.1 - Prob. 41ESCh. 7.1 - For security purpose, a company is starting to...Ch. 7.2 - Prob. 1ESCh. 7.2 - Prob. 2ESCh. 7.2 - Prob. 3ESCh. 7.2 - Prob. 4ESCh. 7.2 - Prob. 5ESCh. 7.2 - Prob. 6ESCh. 7.2 - Prob. 7ESCh. 7.2 - Prob. 8ESCh. 7.2 - Prob. 9ESCh. 7.2 - Prob. 10ESCh. 7.2 - Prob. 11ESCh. 7.2 - Prob. 12ESCh. 7.2 - Prob. 13ESCh. 7.2 - Prob. 14ESCh. 7.2 - Prob. 15ESCh. 7.2 - Prob. 16ESCh. 7.2 - Prob. 17ESCh. 7.2 - Prob. 18ESCh. 7.2 - Prob. 19ESCh. 7.2 - Prob. 20ESCh. 7.2 - Prob. 21ESCh. 7.2 - Prob. 22ESCh. 7.2 - Prob. 23ESCh. 7.2 - Prob. 24ESCh. 7.2 - Prob. 25ESCh. 7.2 - Prob. 26ESCh. 7.2 - Prob. 27ESCh. 7.2 - Prob. 28ESCh. 7.2 - Prob. 29ESCh. 7.2 - Prob. 30ESCh. 7.2 - Prob. 31ESCh. 7.2 - Prob. 32ESCh. 7.2 - Prob. 33ESCh. 7.2 - Prob. 34ESCh. 7.2 - Prob. 35ESCh. 7.2 - Prob. 36ESCh. 7.2 - Prob. 37ESCh. 7.2 - Prob. 38ESCh. 7.2 - Prob. 39ESCh. 7.2 - Prob. 40ESCh. 7.2 - Solve. Some of these exercises may be solved using...Ch. 7.2 - Prob. 42ESCh. 7.2 - Prob. 43ESCh. 7.2 - Prob. 44ESCh. 7.2 - Prob. 45ESCh. 7.2 - Prob. 46ESCh. 7.2 - Prob. 47ESCh. 7.2 - Prob. 48ESCh. 7.2 - Prob. 49ESCh. 7.2 - Prob. 50ESCh. 7.2 - Prob. 51ESCh. 7.2 - Prob. 52ESCh. 7.2 - Prob. 53ESCh. 7.2 - Prob. 54ESCh. 7.2 - Prob. 55ESCh. 7.2 - Prob. 56ESCh. 7.2 - Prob. 57ESCh. 7.2 - Prob. 58ESCh. 7.2 - Prob. 59ESCh. 7.2 - Prob. 60ESCh. 7.2 - Is it possible to evaluate P65 Explain why or why...Ch. 7.2 - Prob. 62ESCh. 7.2 - Prob. 63ESCh. 7.2 - Prob. 64ESCh. 7.2 - Explain why P55 can be calculated but is not...Ch. 7.2 - Prob. 66ESCh. 7.2 - Prob. 67ESCh. 7.2 - Prob. 68ESCh. 7.3 - Prob. 1ESCh. 7.3 - Evaluate each combination. 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