The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified. Concept Introduction: In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion. In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

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Answer 1

Question

Chapter 7, Problem 140QP

Interpretation Introduction

Interpretation:

The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified.

Concept Introduction:

In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion.

In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

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Answer 2

Question

Chapter 7, Problem 140QP

Interpretation Introduction

Interpretation:

The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified.

Concept Introduction:

In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion.

In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 7, Problem 140QP

Interpretation Introduction

Interpretation:

The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified.

Concept Introduction:

In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion.

In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

Expert Solution & Answer

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Answer 4

Question

Chapter 7, Problem 140QP

Interpretation Introduction

Interpretation:

The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified.

Concept Introduction:

In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion.

In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

Expert Solution & Answer

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Answer 5

Chapter 7, Problem 140QP

Interpretation Introduction

Interpretation:

The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified.

Concept Introduction:

In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion.

In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

Answer 6

Chapter 7, Problem 140QP

Interpretation Introduction

Interpretation:

The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified.

Concept Introduction:

In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion.

In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

Answer 7

Chapter 7, Problem 140QP

Interpretation Introduction

Interpretation:

The ion for which the size is decreased when solid sodium and chlorine gas react in order to form NaCl is to be identified.

Concept Introduction:

In the formation of a cation, the number of electrons decreases while the nuclear charge remains the same. The protons pull the remaining electrons closer to the nucleus. So, there is a decrease in the size of the ion.

In the formation of an anion, the number of electrons increases. The protons cannot hold the electrons close to the nucleus and hence, the size of the ion increases.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 7 - Prob. 1QC Ch. 7 - Prob. 2QC Ch. 7 - Prob. 3QC Ch. 7 - Prob. 4QC Ch. 7 - Prob. 5QC Ch. 7 - Prob. 6QC Ch. 7 - Prob. 7QC Ch. 7 - Prob. 1PP Ch. 7 - Prob. 2PP Ch. 7 - Prob. 3PP

Solution Summary: The author analyzes how the ion's size decreases when sodium and chlorine gas react to form NaCl.

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