OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI
OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI
8th Edition
ISBN: 9781305271579
Author: Butler
Publisher: IACCENGAGE
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Chapter 7, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The hybridization of each carbon atom in following structure should be determined.

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  1

Concept Introduction:

The process of the mixing of orbitals having similar symmetry and energy to results equal number of orbitals is known as hybridization.

The formed orbitals are known as hybrid orbitals.

Carbon belongs to group 4 of the periodic table and its atomic number is 6.

The electronic configuration of carbon is: 1s22s22p2

In the hybridization, carbon uses 2s and 2p orbitals.

For example:

In case of sp3 hybridization, one 2s and three 2p orbitals of carbon combine to form four sp3 hybrid orbitals.

The electronic configuration of carbon before and after sp3 hybridization is:

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  2

(b)

Interpretation Introduction

Interpretation:

The hybridization of each carbon atom in following structure should be determined.

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  3

Concept Introduction:

The process of the mixing of orbitals having similar symmetry and energy to results equal number of orbitals is known as hybridization.

The formed orbitals are known as hybrid orbitals.

Carbon belongs to group 4 of the periodic table and its atomic number is 6.

The electronic configuration of carbon is: 1s22s22p2

In the hybridization, carbon uses 2s and 2p orbitals.

For example:

In case of sp3 hybridization, one 2s and three 2p orbitals of carbon combine to form four sp3 hybrid orbitals.

The electronic configuration of carbon before and after sp3 hybridization is:

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  4

(c)

Interpretation Introduction

Interpretation:

The hybridization of each carbon atom in following structure should be determined.

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  5

Concept Introduction:

The process of the mixing of orbitals having similar symmetry and energy to results equal number of orbitals is known as hybridization.

The formed orbitals are known as hybrid orbitals.

Carbon belongs to group 4 of the periodic table and its atomic number is 6.

The electronic configuration of carbon is: 1s22s22p2

In the hybridization, carbon uses 2s and 2p orbitals.

For example:

In case of sp3 hybridization, one 2s and three 2p orbitals of carbon combine to form four sp3 hybrid orbitals.

The electronic configuration of carbon before and after sp3 hybridization is:

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  6

(d)

Interpretation Introduction

Interpretation:

The hybridization of each carbon atom in following structure should be determined.

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  7

Concept Introduction:

The process of the mixing of orbitals having similar symmetry and energy to results equal number of orbitals is known as hybridization.

The formed orbitals are known as hybrid orbitals.

Carbon belongs to group 4 of the periodic table and its atomic number is 6.

The electronic configuration of carbon is: 1s22s22p2

In the hybridization, carbon uses 2s and 2p orbitals.

For example:

In case of sp3 hybridization, one 2s and three 2p orbitals of carbon combine to form four sp3 hybrid orbitals.

The electronic configuration of carbon before and after sp3 hybridization is:

  OWLV2 FOR OXTOBY/GILLIS/BUTLER'S PRINCI, Chapter 7, Problem 13P , additional homework tip  8

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