Mercury in the environment can exist in oxidation states 0, +1, and +2. One major question in environmental chemistry research is how to best measure the oxidation state of mercury in natural systems; this is made more complicated by the fact that mercury can be reduced or oxidized on surfaces differently than it would be if it were free in solution. XPS, X-ray photoelectron spectroscopy, is a technique related to PES (see Exercise 7.111 ), but instead of using ultraviolet light to eject valence electrons, X rays are used to eject core electrons. The energies of the coreelectrons are different for different oxidation states of the element. In one set of experiments, researchers examined mercury contamination of minerals in water. They measured the XPS signals that corresponded to electrons ejected from mercury's 4f orbitals at 105 eV, from an X-ray source that provided 1253.6 eV of energy (1 ev = 1.602 x 10 19J). The oxygen on the mineral surface gave emitted electron energies at 531 eV, corresponding to the 1s orbital of oxygen. Overall the researchers concluded that oxidation states were +2 for Hg and -2 for 0. (a) Calculate the wavelength of the X rays used in this experiment. (b) Compare the energies of the 4f electrons in mercury and the 1s electrons in oxygen from these data to the first ionization energies of mercury and oxygen from the data in this chapter. (c) Write out the ground-state electron configurations for He2+ and 02- ; which electrons are the valence electrons in each case?
Want to see the full answer?
Check out a sample textbook solutionChapter 7 Solutions
CHM 101 VOL 1 2014 >IC<
- Draw the predominant form of arginine at pH = 7.9. The pKa of the side chain is 12.5. Include proper stereochemistry. H2N OH NH H₂N 'N' છ H pH = 7.9 Select to Drawarrow_forwardPlease correct answer and don't used hand raitingarrow_forward142. A mixture of H2(g) and N2(g) has a density of 0.216 g/liter at 300 K and 500 torr. What is the mole fraction composition of the mixture?arrow_forward
- One liter of N2(g) at 2.1 bar and two liters of Ar(g) at 3.4 bar are mixed in a 4.0 liter flask to form an ideal gas mixture. Calculate the value of the final pressure of the mixture if the initial and final temperature of the gases are the same. Repeat this calculation if the initial temperature of the N2(g) and Ar(g) are 304 K and 402 K, respectively, and the final temperature of the mixture is 377 K.arrow_forward10 5 4. These four 'H NMR spectra were recorded from different isomers with molecular formula CsH,CIO. They all contain a carbonyl group. Determine the structure of the different isomers. 0 10 5 0 10 5 10 9 8 7 6 5 4 3. 1 0 9 10 10 66 9 0 10 9 10 5 1 8 7 6 5 3 2 -a 8 7 6 5 1 10 9 8 7 6 5 22 2 1 0 3 2 16 1 0 3 2 1 2 6 0arrow_forwardUse the expression below to ⚫ calculate its value and report it to the proper number of significant digits (you may need to round your answer). ⚫ calculate the % error (or % relative error or % inherent error) ⚫ calculate the absolute error. (20.54±0.02 × 0.254±0.003) / (3.21±0.05) = Value: % Error: Absolute error: ± | % (only 1 significant digit) (only 1 significant digit)arrow_forward
- In each case (more ductile, more brittle, more tough or resistant), indicate which parameter has a larger value. parameter Elastic limit Tensile strength more ductile Strain at break Strength Elastic modulus more fragile more tough or resistantarrow_forwardNonearrow_forwardWhat functional groups are present in this IRarrow_forward
- In each case (more ductile, more brittle, more tough or resistant), indicate which parameter has a larger value. parameter Elastic limit Tensile strength more ductile Strain at break Strength Elastic modulus more fragile more tough or resistantarrow_forward4) A typical bottle of pop holds carbon dioxide at a pressure of 5 atm. What is the concentration of carbon dioxide in th solution? 5) A stream flowing over rocks and such is exposed to the atmosphere and well aerated. What would be the nitrogen concentration in the water at 25°C? (Air pressure is 1.000 bar.)arrow_forwardUse the expression below to ⚫ calculate its value and report it to the proper number of significant digits (you may need to round your answer). ⚫ calculate the % error (or % relative error or % inherent error) ⚫ calculate the absolute error. (30.078±0.003) - (20.174±0.001) + (9.813±0.005) = Value: % Error: absolute error: ± % (only 1 significant digit) (only 1 significant digit)arrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning