Explanation (a) 10 th percentile By referring the table 6.3 ,Z-score for a data value corresponding to 9.68 is − 1.3 and Z − s c o r e For a data value corresponding to 11.51 is − 1.2 . Therefore, the approximate Z-score for a data value in the 10 t h percentile is − 1.2816 . Number of standard deviations that lies below the mean of the given data is 1.2816 (b) 35 t h percentile : By referring the table 6.3 ,Z-score for a data value corresponding to 34.46 percentile is − 0.40 and Z − s c o r e for a data value corresponding to 36.32 percentile is − 0.35 Therefore, the approximate Z-score for a data value in the 35 t h percentile is − 0...

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Chapter 6.C, Problem 32E

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Using table $6.3$ , we have to find approximate standard score and number of standard deviations that the value lies above or below the mean of the given data values.

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Chapter 6.C, Problem 31E

Chapter 6.C, Problem 33E

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Using table 6.3 , we have to find approximate standard score and number of standard deviations that the value lies above or below the mean of the given data values.