Explanation (a) 20 th percentile By referring the table 6.3 ,Z-score for a data value corresponding to 21.19 is − 0.85 and Z − s c o r e For a data value corresponding to 21.19 is − 0.80 . Therefore, the approximate Z-score for a data value in the 20 t h percentile is − 0.83 . Number of standard deviations that lies below the mean of the given data is 0.83 (b) 80 t h percentile : By referring the table 6.3 ,Z-score for a data value corresponding to 78.81 percentile is 0.80 and Z − s c o r e for a data value corresponding to 80.28 percentile is 0.85 Therefore, the approximate Z-score for a data value in the 80 t h percentile is 0...

6th Edition

ISBN: 8220100802713

Author: Briggs

Publisher: PEARSON

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Chapter 6.C, Problem 31E

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Using table $6.3$ , we have to find approximate standard score and number of standard deviations that the value lies above or below the mean of the given data values.

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Chapter 6.C, Problem 30E

Chapter 6.C, Problem 32E

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Using table 6.3 , we have to find approximate standard score and number of standard deviations that the value lies above or below the mean of the given data values.