Explanation Property used: The zero-factor property: If a ⋅ b = 0 then a = 0 or b = 0 . Calculation: The possible factors of 4 x 2 is ( 4 x ) ⋅ ( x ) and ( 2 x ) ⋅ ( 2 x ) as well as the possible factors of − 3 is − 1 ( 3 ) and 1 ( − 3 ) . Obtain the factor of 4 x 2 + x − 3 = 0 . Possible factors Sum of products of outer and inner Terms ( 4 x − 1 ) ( x + 3 ) 12 x − x = 11 x ( 4 x + 1 ) ( x − 3 ) − 12 x + x = − 11 x ( 2 x − 1 ) ( 2 x + 3 ) 6 x − 2 x = 4 x ( 2 x + 1 ) ( 2 x − 3 ) − 6 x + 2 x = − 4 x ( 4 x + 3 ) ( x − 1 ) − 4 x + 3 x = − x ( 4 x − 3 ) ( x + 1 ) 4 x − 3 x = x ( 2 x + 3 ) (

Books a la carte edition for A Survey of Mathematics with Applications (10th Edition)

10th Edition

ISBN: 9780134112268

Author: Christine D. Abbott, Allen R. Angel, Dennis Runde

Publisher: PEARSON

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Chapter 6.9, Problem 58E

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Chapter 6.9, Problem 57E

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Chapter 6 Solutions

Books a la carte edition for A Survey of Mathematics with Applications (10th Edition)

Ch. 6.1 - A letter of the alphabet used to represent numbers...Ch. 6.1 - Prob. 2E Ch. 6.1 - A collection of variables, numbers, grouping...Ch. 6.1 - The number or numbers that replace the variable to...Ch. 6.1 - The parts that are added or subtracted in an...Ch. 6.1 - Terms that have the same variables with the same...Ch. 6.1 - The numerical part of a term is called its...Ch. 6.1 - Prob. 8E Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E

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