Explanation Given info: The values of p = 0.8 and n = 20 . Calculation: The value is p = 0.8 . The value of q is 0.2 (1–0.2). The total number n is 20. Requirement check: Condition 1: n p ≥ 5 Condition 2: n q ≥ 5 Condition 1: n p ≥ 5 Substitute 20 for n and 0.8 for p in the np . n p = 20 × 0.8 = 16 Thus, the given requirement 16 ≥ 5 is satisfied. Condition 2: n q ≥ 5 Substitute 20 for n and 0

Essentials of Statistics, Books a la Carte Edition (5th Edition)

5th Edition

ISBN: 9780321926739

Author: Mario F. Triola

Publisher: PEARSON

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Chapter 6.7, Problem 7BSC

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To obtain: P(more than 11) if requirements of np≥5 and nq≥5 are both satisfied otherwise state the normal approximation is not appropriate if np<5 or nq<5 .

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Chapter 6.7, Problem 6BSC

Chapter 6.7, Problem 8BSC

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To obtain: P ( more than 11 ) if requirements of n p ≥ 5 and n q ≥ 5 are both satisfied otherwise state the normal approximation is not appropriate if n p < 5 or n q < 5 .

Solution Summary: The author explains that the normal approximation should not be used because the requirement nq5 is not satisfied.

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To obtain: P(more than 11) if requirements of np≥5 and nq≥5 are both satisfied otherwise state the normal approximation is not appropriate if np<5 or nq<5 .

Want to see the full answer?

Chapter 6 Solutions

To obtain: P ( more than 11 ) if requirements of n p ≥ 5 and n q ≥ 5 are both satisfied otherwise state the normal approximation is not appropriate if n p &lt; 5 or n q &lt; 5 .

Solution Summary: The author explains that the normal approximation should not be used because the requirement nq5 is not satisfied.

Concept explainers

Videos

To obtain: P(more than 11) if requirements of np≥5 and nq≥5 are both satisfied otherwise state the normal approximation is not appropriate if np<5 or nq<5 .

Want to see the full answer?

Chapter 6 Solutions

To obtain: P ( more than 11 ) if requirements of n p ≥ 5 and n q ≥ 5 are both satisfied otherwise state the normal approximation is not appropriate if n p < 5 or n q < 5 .