Explanation Method used: Solving Equations Involving Fractions: 1. Multiply each term of the equation by the LCD of all the denominators. This should eliminate all fractions from the equation. 2. Solve the resulting equation using previous methods. 3. Check the solution in the original equation. Calculation: The given equation is, 2 x + 1 − 1 x = − 2 x 2 + x . Change the numerator of the equation 2 x + 1 − 1 x = − 2 x 2 + x on the right to 1 and obtain the new equation as 2 x + 1 − 1 x = − 1 x 2 + x . Use the above method to solve the equation 2 x + 1 − 1 x = − 1 x 2 + x for x as follows. 2 x ( x + 1 ) x + 1 − x ( x + 1 ) x = − x ( x + 1 ) x 2 + x ( Each term is multiplied by LCD x ( x + 1 ) ) 2 x ( x + 1 ) x + 1 − x ( x + 1 ) x = − x ( x + 1 ) x ( x + 1 ) 2 x − ( x + 1 ) = − 1

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ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 6.7, Problem 4E

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To change: The numerator of the equation 2x+1−1x=−2x2+x on the right to 1 and solve for x.

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Chapter 6.7, Problem 3E

Chapter 6.7, Problem 5E

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Chapter 6 Solutions

Basic Technical Mathematics

Ch. 6.1 - Prob. 1PE Ch. 6.1 - Prob. 2PE Ch. 6.1 - Prob. 3PE Ch. 6.1 - Prob. 4PE Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E

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To change: The numerator of the equation 2 x + 1 − 1 x = − 2 x 2 + x on the right to 1 and solve for x .

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To change: The numerator of the equation 2x+1−1x=−2x2+x on the right to 1 and solve for x.

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