Explanation Procedure used: Factoring a x 2 + b x + c , a ≠ 1 using trial and error, where a, band c have no common factors: “Step 1: List the possibilities for the first terms of each binomial whose product is a x 2 . Step 2: List the possibilities for the last terms of each binomial whose product is b . Step 3: Write all the combinations of factors found in step 1 and step 2. Multiply the binomials until a product that equals the trinomial is found”. Calculation: Obtain the factor of the trinomial 6 s 2 + 19 s t − 20 t 2 as follows. List the possible ways for the first terms of each binomial whose product is 6 s 2 . Here, there is possibility to represent the first term 6 s 2 are ( 6 s + _ _ _ ) ( s + _ _ _ ) and ( 2 s + _ _ _ ) ( 3 s + _ _ _ ) List the possibilities for the last terms of each binomial whose product is − 20 t 2 as shown below in Table 1. Factors of − 20 t 2 t , − 20 t − t , 20 t 10 t , − 2 t − 4 t , 5 t 4 t , − 5 t − 10 t , 2 t Table 1 To produce a positive sum that is b = 19 s , consider the positive factors. Write all the combinations of factors found in above steps. Multiply the binomials until a product that equals to the trinomial is found. The second term of ( 6 x + _ _ _ ) ( x + _ _ _ ) and ( 2 x + _ _ _ ) ( 3 x + _ _ _ ) has the following possibilities and the product is shown in Table 2

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ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 6.2, Problem 3PE

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To factor: The expression 6s2+19st−20t2 by trial and error.

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To factor: The expression 6 s 2 + 19 s t − 20 t 2 by trial and error.

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