Chapter 6.6, Problem 96E

To determine

To prove: The rectangular equation is $y=-\frac{16{\sec }^2\theta }{v_0^2}{x}^2+\left(\tan \theta \right)x+h$ for the parametric equation $x=\left(v_0\cos \theta \right)t$ and $y=h+\left(v_0\sin \theta \right)t-16t^2$ for the motion of a projectile by eliminating the variable $t$.