
Concept explainers
To calculate: .The equation for the value of x .

Answer to Problem 72E
The required value of x is 1 .
Explanation of Solution
Given Information:
The given equation is 52x+20⋅5x−125=0 .
Formula Used:
Power rule of logarithmic functions.
logaxp=plogax
Where a is the base, x is the variable and p is the power of variable.
Property of logarithm.
logaa=1
Quadratic formula.
If ax2+bx+c=0 then x=−b±√b2−4ac2a
Where a,b,c are constant and a≠0
Calculation:
Consider the equation is 52x+20⋅5x−125=0 .
Substitute y for 5x in the above equation.
y2+20y−125=0
Use quadratic formula of the above equation.
y=−b±√b2−4ac2a
Substitute 1 for a , 20 for b and −125 for c in the above formula.
y=−20±√(20)2−4(1)(−125)2(1)
Simplify the above equation.
y=−20±√(20)2−4(1)(−125)2(1)=−20±√400+5002=−20±√9002=−20±302
Simplify the equation.
y=−20±302=−20+302,−20−302=102.−502=5,−25
Now, y=5
Substitute 5x for y in the above result.
5x=5
Take logarithm each side with base 5 .
log55x=log55
Use power rule of logarithm logaxp=plogax in the above equation.
xlog55=log55
Use property of logarithm logaa=1 in the above equation.
x(1)=1x=1
And
y=−25
Substitute 5x for y in the above result.
5x=−25
Take logarithm each side with base 5 .
log55x=log5(−25)
It is known that loga(−x) is does not exist.
Hence, the required value of x is 1 .
Chapter 6 Solutions
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