Industrial Motor Control
7th Edition
ISBN: 9781133691808
Author: Stephen Herman
Publisher: Cengage Learning
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Chapter 66, Problem 1RQ
To determine
The reason behind the fact that the voltage that is connected to the inverting terminal is more positive than the voltage to the non-inverting terminal, whether the input will be positive or negative.
Expert Solution & Answer
Explanation of Solution
The operational amplifier are the devices that are used to amplify the signals. The op amp have two inputs and one output terminals. The output is generally the amplification of the difference of voltages at the input, therefore it is also known as the differential amplifier.
In case the voltage is connected to the inverting input is more positive than the non-inverting input then the output is negative as the output is inverted.
Thus, if the voltage that is connected to the non-inverting input, then the output is negative.
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Student Name:
Student Id:
College of Applied Engineering
Al-Muzahmiyah Branch
Statics (AGE 1330) Section-1483
Quiz-2
Time: 20 minutes
Date: 16/02/2025
Q.1. A swinging door that weighs w=400.0N is supported by
hinges A and B so that the door can swing about a vertical'
axis passing through the hinges (as shown in below figure).
The door has a width of b=1.00m and the door slab has a
uniform mass density. The hinges are placed symmetrically
at the door's edge in such a way that the door's weight is
evenly distributed between them. The hinges are separated
by distance a=2.00m. Find the forces on the hinges when
the door rests half-open. Draw Free body diagram also.
[5 marks]
[CLO 1.2]
Mool
b
ర
a
2.0 m
B
1.0 m
For the walking-beam mechanism shown in Figure 3, find and plot the x and y coordinates of the
position of the coupler point P for one complete revolution of the crank O2A. Use the coordinate
system shown in Figure 3. Hint: Calculate them first with respect to the ground link 0204 and
then transform them into the global XY coordinate system.
y
-1.75
Ꮎ
Ꮎ
4
= 2.33
0242.22
L4
x
AP = 3.06
L2 = 1.0
W2
31°
B
03 L3 = 2.06
P
1
8
5
.06
6
7
P'
The link lengths, gear ratio (2), phase angle (Ø), and the value of 02 for some geared five bar
linkages are defined in Table 2. The linkage configuration and terminology are shown in Figure
2. For the rows assigned, find all possible solutions for angles 03 and 04 by the vector loop
method. Show your work in details: vector loop, vector equations, solution procedure.
Table 2
Row
Link 1 Link 2
Link 3
Link 4
Link 5
λ
Φ
Ө
a
6
1
7
9
4
2
30°
60°
P
y 4
YA
B
b
R4
R3
YA
A
Gear ratio:
a
02
d
05
r5
R5
R2
Phase angle: = 0₂-202
R1
05
02
r2
Figure 2.
04
X
Chapter 66 Solutions
Industrial Motor Control
Ch. 66 - Prob. 1RQCh. 66 - Prob. 2RQCh. 66 - Prob. 3RQCh. 66 - Prob. 4RQCh. 66 - Prob. 5RQCh. 66 - Prob. 6RQCh. 66 - Name two effects of negative feedback.Ch. 66 - Refer to Figure 668. If resistor R1 is 200 ohms...Ch. 66 - Refer to Figure 66–9. If resistor R1 is 470 ohms...Ch. 66 - What is the purpose of the hysteresis loop when...
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