Explanation Given: The radius of the hemisphere: r = 0.8 meter Density of the material is 600 k g / m 3 Calculation: Now, first compute the gravitational force on a thin layer of width δ y . The origin of the coordinate system at the center of the hemisphere since, this leads to simple formula for the radius of the cross-section. The cross-sectional height y is a circle of radius r is 0.64 − y 2 and area is A ( y ) = π ( 0.64 − y 2 ) A thin layer of volume A ( y ) d y and mass obtained by multiplying the density. As density = mass volume ⇒ mass = volume × density ⇒ mass = A ( y ) δ y × 600 Now, as per newton’s rule, force of the solid box is f = m g f = A ( y ) δ y × 600 × 9.8 f = ( 9.8 ) 600 π ( 0.64 − y 2 ) δ y N The layer has to be lifted at a vertical distance ( 6 − y ) . The work on layer is 7680 π ( 0.64 − y 2 ) δ y × ( 6 − y ) = L ( y ) d y L ( y ) d y = 7680 π ( 0.64 − y 2 ) × ( 6 − y ) L ( y ) d y = 7680 π ( 3

4th Edition

ISBN: 9781319279813

Author: Rogawski

Publisher: MAC HIGHER

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Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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System that uses coordinates to uniquely determine the position of points. The most common coordinate system is the Cartesian system, where points are given by distance along a horizontal x-axis and vertical y-axis from the origin. A polar coordinate system locates a point by its direction relative to a reference direction and its distance from a given point. In three dimensions, it leads to cylindrical and spherical coordinates.

Chapter 6.5, Problem 14E

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To calculate:

the work against gravity required to build the structure out of a lightweight.

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Chapter 6.5, Problem 13E

Chapter 6.5, Problem 15E

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For the following function f and real number a, a. find the slope of the tangent line mtan = f' (a), and b. find the equation of the tangent line to f at x = a. f(x)= 2 = a = 2 x2 a. Slope: b. Equation of tangent line: y

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Chapter 6 Solutions

CALCULUS:EARLY TRANS.-SAPLINGPLUS

Ch. 6.1 - Prob. 1PQ Ch. 6.1 - Prob. 2PQ Ch. 6.1 - Prob. 3PQ Ch. 6.1 - Prob. 4PQ Ch. 6.1 - Prob. 5PQ Ch. 6.1 - Prob. 6PQ Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E

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Prob. 40E Ch. 6.4 - Prob. 41E Ch. 6.4 - Prob. 42E Ch. 6.4 - Prob. 43E Ch. 6.4 - Prob. 44E Ch. 6.4 - Prob. 45E Ch. 6.4 - Prob. 46E Ch. 6.4 - Prob. 47E Ch. 6.4 - Prob. 48E Ch. 6.4 - Prob. 49E Ch. 6.4 - Prob. 50E Ch. 6.4 - Prob. 51E Ch. 6.4 - Prob. 52E Ch. 6.4 - Prob. 53E Ch. 6.4 - Prob. 54E Ch. 6.4 - Prob. 55E Ch. 6.4 - Prob. 56E Ch. 6.4 - Prob. 57E Ch. 6.4 - Prob. 58E Ch. 6.4 - Prob. 59E Ch. 6.4 - Prob. 60E Ch. 6.4 - Prob. 61E Ch. 6.4 - Prob. 62E Ch. 6.4 - Prob. 63E Ch. 6.4 - Prob. 64E Ch. 6.4 - Prob. 65E Ch. 6.4 - Prob. 66E Ch. 6.5 - Prob. 1PQ Ch. 6.5 - Prob. 2PQ Ch. 6.5 - Prob. 3PQ Ch. 6.5 - Prob. 4PQ Ch. 6.5 - Prob. 1E Ch. 6.5 - Prob. 2E Ch. 6.5 - Prob. 3E Ch. 6.5 - Prob. 4E Ch. 6.5 - Prob. 5E Ch. 6.5 - Prob. 6E Ch. 6.5 - Prob. 7E Ch. 6.5 - Prob. 8E Ch. 6.5 - Prob. 9E Ch. 6.5 - Prob. 10E Ch. 6.5 - Prob. 11E Ch. 6.5 - Prob. 12E Ch. 6.5 - Prob. 13E Ch. 6.5 - Prob. 14E Ch. 6.5 - Prob. 15E Ch. 6.5 - Prob. 16E Ch. 6.5 - Prob. 17E Ch. 6.5 - Prob. 18E Ch. 6.5 - Prob. 19E Ch. 6.5 - Prob. 20E Ch. 6.5 - Prob. 21E Ch. 6.5 - Prob. 22E Ch. 6.5 - Prob. 23E Ch. 6.5 - Prob. 24E Ch. 6.5 - Prob. 25E Ch. 6.5 - Prob. 26E Ch. 6.5 - Prob. 27E Ch. 6.5 - Prob. 28E Ch. 6.5 - Prob. 29E Ch. 6.5 - Prob. 30E Ch. 6.5 - Prob. 31E Ch. 6.5 - Prob. 32E Ch. 6.5 - Prob. 33E Ch. 6.5 - Prob. 34E Ch. 6.5 - Prob. 35E Ch. 6.5 - Prob. 36E Ch. 6.5 - Prob. 37E Ch. 6.5 - Prob. 38E Ch. 6.5 - Prob. 39E Ch. 6.5 - Prob. 40E Ch. 6.5 - Prob. 41E Ch. 6.5 - Prob. 42E Ch. 6.5 - Prob. 43E Ch. 6 - Prob. 1CRE Ch. 6 - Prob. 2CRE Ch. 6 - Prob. 3CRE Ch. 6 - Prob. 4CRE Ch. 6 - Prob. 5CRE Ch. 6 - Prob. 6CRE Ch. 6 - Prob. 7CRE Ch. 6 - Prob. 8CRE Ch. 6 - Prob. 9CRE Ch. 6 - Prob. 10CRE Ch. 6 - Prob. 11CRE Ch. 6 - Prob. 12CRE Ch. 6 - Prob. 13CRE Ch. 6 - Prob. 14CRE Ch. 6 - Prob. 15CRE Ch. 6 - Prob. 16CRE Ch. 6 - Prob. 17CRE Ch. 6 - Prob. 18CRE Ch. 6 - Prob. 19CRE Ch. 6 - Prob. 20CRE Ch. 6 - Prob. 21CRE Ch. 6 - Prob. 22CRE Ch. 6 - Prob. 23CRE Ch. 6 - Prob. 24CRE Ch. 6 - Prob. 25CRE Ch. 6 - Prob. 26CRE Ch. 6 - Prob. 27CRE Ch. 6 - Prob. 28CRE Ch. 6 - Prob. 29CRE Ch. 6 - Prob. 30CRE Ch. 6 - Prob. 31CRE Ch. 6 - Prob. 32CRE Ch. 6 - Prob. 33CRE Ch. 6 - Prob. 34CRE Ch. 6 - Prob. 35CRE Ch. 6 - Prob. 36CRE Ch. 6 - Prob. 37CRE Ch. 6 - Prob. 38CRE Ch. 6 - Prob. 39CRE Ch. 6 - Prob. 40CRE Ch. 6 - Prob. 41CRE Ch. 6 - Prob. 42CRE Ch. 6 - Prob. 43CRE Ch. 6 - Prob. 44CRE Ch. 6 - Prob. 45CRE Ch. 6 - Prob. 46CRE Ch. 6 - Prob. 47CRE Ch. 6 - Prob. 48CRE Ch. 6 - Prob. 49CRE Ch. 6 - Prob. 50CRE Ch. 6 - Prob. 51CRE Ch. 6 - Prob. 52CRE Ch. 6 - Prob. 53CRE Ch. 6 - Prob. 54CRE

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the work against gravity required to build the structure out of a lightweight.

Solution Summary: The author calculates the work against gravity required to build the structure out of a lightweight.

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To calculate: the work against gravity required to build the structure out of a lightweight.

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Chapter 6 Solutions

To calculate:

the work against gravity required to build the structure out of a lightweight.