Chapter 6.4, Problem 83E

To determine

The work done in pullingthe wagon 50 feetif a toy wagon is pulled by exerting a force of25 pounds on a handle that makesa ${20}^0$ angle with thehorizontal.

Answer to Problem 83E

The work done in pullingthe wagon is $\text{1174}\text{.62ft-lb}$

Explanation of Solution

Given info:

  

  $\begin{array}{l}\overrightarrow{s}=50ft\\ \overrightarrow{F}=25lb\\ \theta ={20}^0\end{array}$

Formula used:

Work done

  $W=\overrightarrow{F}.\overrightarrow{s}=\left|F\right|\left|s\right|\cos \theta$

Where $\overrightarrow{F}$ is the force, $\overrightarrow{s}$ is the displacement and $\theta$ is the angle between force and displacement.

Calculation:

We have

  $\begin{array}{l}W=\overrightarrow{F}.\overrightarrow{s}=\left|F\right|\left|s\right|\cos \theta \\ W=\overrightarrow{F}.\overrightarrow{s}=25\times 50\times \cos {20}^0=\text{1174}\text{.62ft-lb}\end{array}$

The work done in pullingthe wagon is $\text{1174}\text{.62ft-lb}$

Conclusion:

Thus,thework done in pullingthe wagon is $\text{1174}\text{.62ft-lb}$