EBK COMPUTER SYSTEMS
EBK COMPUTER SYSTEMS
3rd Edition
ISBN: 8220101459107
Author: O'HALLARON
Publisher: YUZU
Expert Solution & Answer
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Chapter 6.4, Problem 6.13PP

A)

Explanation of Solution

Cache entry and cache byte:

The program running on a machine references the 1-byte word at address “0x0E34”. Hexadecimal is a number system of base 16As and as  hex system has 16 digits, the extra needed 6 digits are represented by the first 6 letters of English alphabet which means “ 0,1,2,3,4,5,6,7,8” represents “9,A,?B,?C,?D,?E,?F” respectively in decimal system.

First, one needs to convert the hexadecimal address into binary form:

For example, “0x0E34” is a hexadecimal address and can be converted into binary:

(0x0E34)16=(000734)10=(0000 0000 0000 1110 0011 0100)2

One needs to consider the following set associative (S, E, B, m) = (8, 4, 4, 13). The derived value will be as follows:

The Index (CI):

s=log2(S)   =log2(23) = 3 log2

B)

Explanation of Solution

Memory reference:

The address format (1 bit per box) for address “0x0E34” is hence represented as:

CTCTCTCTCTCTCTCTCICICICOCO
0111000110100

The memory reference for the above address format “0x0E34

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