Given Information : A 4-way set associative cache is given: Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A 1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02 2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E 3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2 4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA 5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A 6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1 FA 93 EB 48 7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30 The number of physical address bits is represented by “m”. The size of cache represented is by “C”. The block of size in bytes is represented as “B”. Associativity is represented as “E”. The number of cache sets is represented by “S”. The number of tag bits is represented by “t”. The number of block offset bits is represented as “b”.

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Answer 1

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

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Answer 2

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Expert Solution & Answer

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Answer 3

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Expert Solution & Answer

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Answer 4

Question

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Answer 6

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Answer 7

Chapter 6, Problem 6.33HW

Program Plan Intro

Given Information:

A 4-way set associative cache is given:

Index Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3 Tag V Bytes 0-3
0 F0 1 ED 32 0A A2 8A 1 BF 80 1D FC 14 1 EF 09 86 2A BC 0 25 44 6F 1A
1 BC 0 03 3E CD 38 A0 0 16 7B ED 5A BC 1 8E 4C DF 18 E4 1 FB B7 12 02
2 BC 1 54 9E 1E FA B6 1 DC 81 B2 14 00 0 B6 1F 7B 44 74 0 10 F5 B8 2E
3 BE 0 2F 7E 3D A8 C0 1 27 95 A4 74 C4 0 07 11 6B D8 BC 0 C7 B7 AF C2
4 7E 1 32 21 1C 2C 8A 1 22 C2 DC 34 BC 1 BA DD 37 D8 DC 0 E7 A2 39 BA
5 98 0 A9 76 2B EE 54 0 BC 91 D5 92 98 1 80 BA 9B F6 BC 1 48 16 81 0A
6 38 0 5D 4D F7 DA BC 1 69 C2 8C 74 8A 1 A8 CE 7F DA 38 1
FA 93

EB 48
7 8A 1 04 2A 32 6A 9E 0 B1 86 56 0E CC 1 96 30 47 F2 BC 1 F8 1D 42 30

The number of physical address bits is represented by “m”.

The size of cache represented is by “C”.

The block of size in bytes is represented as “B”.

Associativity is represented as “E”.

The number of cache sets is represented by “S”.

The number of tag bits is represented by “t”.

The number of block offset bits is represented as “b”.

Answer 8

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Answer 9

Expert Solution & Answer

Answer 10

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Answer 11

Ch. 6.1 - Prob. 6.1PP Ch. 6.1 - Prob. 6.2PP Ch. 6.1 - Prob. 6.3PP Ch. 6.1 - Prob. 6.4PP Ch. 6.1 - Prob. 6.5PP Ch. 6.1 - Prob. 6.6PP Ch. 6.2 - Prob. 6.7PP Ch. 6.2 - Prob. 6.8PP Ch. 6.4 - Prob. 6.9PP Ch. 6.4 - Prob. 6.10PP

Solution Summary: The author explains that a 4-way set associative cache is given. The number of physical address bits is represented by "m".

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Chapter 6 Solutions

Index	Tag	V	Bytes 0-3	Tag	V	Bytes 0-3	Tag	V	Bytes 0-3	Tag	V	Bytes 0-3
0	F0	1	ED 32 0A A2	8A	1	BF 80 1D FC	14	1	EF 09 86 2A	BC	0	25 44 6F 1A
1	BC	0	03 3E CD 38	A0	0	16 7B ED 5A	BC	1	8E 4C DF 18	E4	1	FB B7 12 02
2	BC	1	54 9E 1E FA	B6	1	DC 81 B2 14	00	0	B6 1F 7B 44	74	0	10 F5 B8 2E
3	BE	0	2F 7E 3D A8	C0	1	27 95 A4 74	C4	0	07 11 6B D8	BC	0	C7 B7 AF C2
4	7E	1	32 21 1C 2C	8A	1	22 C2 DC 34	BC	1	BA DD 37 D8	DC	0	E7 A2 39 BA
5	98	0	A9 76 2B EE	54	0	BC 91 D5 92	98	1	80 BA 9B F6	BC	1	48 16 81 0A
6	38	0	5D 4D F7 DA	BC	1	69 C2 8C 74	8A	1	A8 CE 7F DA	38	1	FA 93 EB 48
7	8A	1	04 2A 32 6A	9E	0	B1 86 56 0E	CC	1	96 30 47 F2	BC	1	F8 1D 42 30