Explanation Given: The provided equation is sin − 1 x + tan − 1 x = π 2 . Calculation: Consider the following equation: sin − 1 x + tan − 1 x = π 2 Isolated inverse function . sin − 1 x + tan − 1 x = π 2 sin − 1 x = π 2 − tan − 1 x x = sin ( π 2 − tan − 1 x ) Use subtract identity and let tan − 1 x = u . So, x = sin ( π 2 − tan − 1 x ) = sin ( π 2 − u ) = sin ( π 2

MyLab Math with Pearson eText -- 24-Month Standalone Access Card -- for Trigonometry

11th Edition

ISBN: 9780135909140

Author: Lial, Margaret, HORNSBY, John, SCHNEIDER, David, DANIELS, Callie

Publisher: PEARSON

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Chapter 6.4, Problem 44E

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To calculate: The solution for the provided following equation: sin−1x+tan−1x=π2

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Chapter 6.4, Problem 43E

Chapter 6.4, Problem 45E

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MyLab Math with Pearson eText -- 24-Month Standalone Access Card -- for Trigonometry

Ch. 6.1 - CONCEPT PREVIEW Fill in the blank(s) to...Ch. 6.1 - CONCEPT PREVIEW Fill in the blank(s) to...Ch. 6.1 - 3. y = cos–1 x means that x = ________ for 0 ≤ y...Ch. 6.1 - 4. The point lies on the graph of y = tan x....Ch. 6.1 - 5. If a function f has an inverse and f(π) = –1,...Ch. 6.1 - CONCEPT PREVIEW Fill in the blank(s) to...Ch. 6.1 - CONCEPT PREVIEW Write a short answer for each of...Ch. 6.1 - Consider the inverse cosine function y = cos1 x,...Ch. 6.1 - 9. Consider the inverse tangent function y =...Ch. 6.1 - 10. Give the domain and range of each inverse...

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The solution for the provided following equation: sin − 1 x + tan − 1 x = π 2

Solution Summary: The author calculates the solution for the provided equation: underset_left0right.

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To calculate: The solution for the provided following equation: sin−1x+tan−1x=π2

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Chapter 6 Solutions