Explanation Given: The expression is: ( 4 y 4 − 17 y 2 + 14 y − 3 ) ÷ ( 2 y − 3 ) . Calculation: Consider the provided expression and rewrite the dividend, 4 y 4 − 17 y 2 + 14 y − 3 = 4 y 4 + 0 y 3 − 17 y 2 + 14 y − 3 Now, use the general procedure for dividing a polynomial that contains more than one term: 2 y − 3 2 y 3 + 3 y 2 − 4 y + 1 4 y 4 + 0 y 3 − 17 y 2 + 14 y − 3 4 y 4 − 6 y _ 3 6 y 3 − 17 y 2 6 y 3 − 9 y 2 _ − 8 y 2 + 14 y

MYLAB MATH F/INTER ALGEBRA 24 MONTHS >I<

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ISBN: 9780136679196

Author: Blitzer

Publisher: PEARSON

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Chapter 6.4, Problem 31ES

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To calculate: The resultant value of the expression (4y4−17y2+14y−3)÷(2y−3).

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Chapter 6.4, Problem 30ES

Chapter 6.4, Problem 32ES

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MYLAB MATH F/INTER ALGEBRA 24 MONTHS >I<

Ch. 6.1 - Check Point 1 Use the rational function in...Ch. 6.1 - Check Point 2 Find the domain of f if...Ch. 6.1 - Prob. 3CP Ch. 6.1 - Prob. 4CP Ch. 6.1 - Prob. 5CP Ch. 6.1 - Prob. 6CP Ch. 6.1 - Prob. 7CP Ch. 6.1 - Prob. 1CAVC Ch. 6.1 - Prob. 2CAVC Ch. 6.1 - Prob. 3CAVC

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The resultant value of the expression ( 4 y 4 − 17 y 2 + 14 y − 3 ) ÷ ( 2 y − 3 ) .

Solution Summary: The author explains the general procedure for dividing a polynomial that contains more than one term.

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To calculate: The resultant value of the expression (4y4−17y2+14y−3)÷(2y−3).

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