In the following exercises, use the binomial approximation 1 − x ≈ 1 − x 2 − x 2 8 − x 3 16 − 5 x 5 128 − 7 x 5 256 for | x | <1 to approximate each number. Compare this value to the value given by a scientific calculator. 193, [T] Recall that the graph of 1 − x 2 is an upper semicircle of radius 1. Integrate the binomial approximation of 1 − x 2 up ro order 8 from x = —1 to x = 1 to estimate π 2 .
In the following exercises, use the binomial approximation 1 − x ≈ 1 − x 2 − x 2 8 − x 3 16 − 5 x 5 128 − 7 x 5 256 for | x | <1 to approximate each number. Compare this value to the value given by a scientific calculator. 193, [T] Recall that the graph of 1 − x 2 is an upper semicircle of radius 1. Integrate the binomial approximation of 1 − x 2 up ro order 8 from x = —1 to x = 1 to estimate π 2 .
In the following exercises, use the binomial approximation
1
−
x
≈
1
−
x
2
−
x
2
8
−
x
3
16
−
5
x
5
128
−
7
x
5
256
for |x| <1 to approximate each number. Compare this value to the value given by a scientific calculator.
193, [T] Recall that the graph of
1
−
x
2
is an upper semicircle of radius 1. Integrate the binomial approximation of
1
−
x
2
up ro order 8 from x = —1 to x = 1 to estimate
π
2
.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Explain the key points and reasons for 12.8.2 (1) and 12.8.2 (2)
Q1:
A slider in a machine moves along a fixed straight rod. Its
distance x cm along the rod is given below for various values of the time. Find the
velocity and acceleration of the slider when t = 0.3 seconds.
t(seconds)
x(cm)
0 0.1 0.2 0.3 0.4 0.5 0.6
30.13 31.62 32.87 33.64 33.95 33.81 33.24
Q2:
Using the Runge-Kutta method of fourth order, solve for y atr = 1.2,
From
dy_2xy +et
=
dx x²+xc*
Take h=0.2.
given x = 1, y = 0
Q3:Approximate the solution of the following equation
using finite difference method.
ly -(1-y=
y = x), y(1) = 2 and y(3) = −1
On the interval (1≤x≤3).(taking h=0.5).
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