(a) Explanation Figure 1 shown below is the free body diagram of the entire machine. Let A and B be the reaction forces at the front wheel and rear wheel respectively. Write the equation to find the sum of moments about wheel A. ∑ M A = W l ( 3.2 m ) − W g ( 1.2 m ) + 2 B ( 4.8 m ) − W m ( 5.6 m ) = 0 (I) Here, W l is the weight of the load applied, W g is he weight at the center of gravity point, B is the reaction force at the rear wheel, W m is the weight of motor unit. Write the sum of y component of forces about front wheel. ∑ F y = 2 A + 2 B − W l − W g − W m = 0 (II) Here, W l is the weight of the load applied, W g is he weight at the center of gravity point, B is the reaction force at the rear wheel, W m is the weight of motor unit. Conclusion: Substitute 75 kN for W l , 100 kN for W g , and 300 kN for W m in equation (I) to get B (b) To determine The forces exerted on the motor unit at C and D.

Vector Mechanics for Engineers: Statics and Dynamics

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ISBN: 9781259638091

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 6.3, Problem 6.97P

(a)

To determine

The reaction at each of the four wheels.

(b)

To determine

The forces exerted on the motor unit at C and D.

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Chapter 6.3, Problem 6.96P

Chapter 6.3, Problem 6.98P

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The reaction at each of the four wheels.

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