Statistics for Business & Economics, Revised (MindTap Course List)
12th Edition
ISBN: 9781285846323
Author: David R. Anderson, Dennis J. Sweeney, Thomas A. Williams, Jeffrey D. Camm, James J. Cochran
Publisher: South-Western College Pub
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Textbook Question
Chapter 6.3, Problem 29E
An Internal Revenue Oversight Board survey found that 82% of taxpayers said that it was very important for the Internal Revenue Service (IRS) to ensure that high-income tax payers do not cheat on their tax returns (The Wall Street Journal, February 11, 2009).
- a. For a sample of eight taxpayers, what is the
probability that at least six taxpayers say that it is very important to ensure that high-income tax payers do not cheat on their tax returns? Use the binomialdistribution probability function shown in Section 5.4 to answer this question. - b. For a sample of 80 taxpayers, what is the probability that at least 60 taxpayers say that it is very important to ensure that high-income tax payers do not cheat on their tax returns? Use the normal approximation of the binomial distribution to answer this question.
- c. As the number of trails in a binomial distribution application becomes large, what is the advantage of using the normal approximation of the binomial distribution to compute probabilities?
- d. When the number of trials for a binominal distribution application becomes large, would developers of statistical software packages prefer to use the binomial distribution probability function shown in Section 5.5 or the normal approximation of the binomial distribution shown in Section 6.3? Explain.
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Students have asked these similar questions
4. (5 pts) Conduct a chi-square contingency test (test of independence) to assess whether
there is an association between the behavior of the elderly person (did not stop to talk,
did stop to talk) and their likelihood of falling. Below, please state your null and
alternative hypotheses, calculate your expected values and write them in the table,
compute the test statistic, test the null by comparing your test statistic to the critical
value in Table A (p. 713-714) of your textbook and/or estimating the P-value, and
provide your conclusions in written form. Make sure to show your work.
Did not stop walking to talk
Stopped walking to talk
Suffered a fall
12
11
Totals
23
Did not suffer a fall | 2
Totals
35
37
14
46
60
T
Question 2
Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples
of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2.
Table 2: Strength Data for Question 2
Sample Number
x1
x2
23
x4
x5
R
1
83.0
2
88.6 78.3 78.8
3
85.7
75.8
84.3
81.2 78.7 75.7 77.0
71.0 84.2
81.0
79.1
7.3
80.2 17.6
75.2
80.4
10.4
4
80.8
74.4
82.5
74.1 75.7 77.5
8.4
5
83.4
78.4
82.6 78.2
78.9
80.3
5.2
File Preview
6
75.3
79.9
87.3 89.7
81.8
82.8
14.5
7
74.5
78.0 80.8
73.4
79.7
77.3
7.4
8
79.2
84.4 81.5 86.0
74.5
81.1
11.4
9
80.5
86.2
76.2 64.1
80.2
81.4
9.9
10
75.7
75.2
71.1 82.1
74.3
75.7
10.9
11
80.0 81.5
78.4 73.8
78.1
78.4
7.7
12
80.6
81.8
79.3
73.8
81.7 79.4
8.0
13
82.7
81.3
79.1
82.0 79.5 80.9
3.6
14
79.2
74.9
78.6 77.7
75.3
77.1
4.3
15
85.5 82.1
82.8 73.4
71.7
79.1
13.8
16
78.8 79.6
80.2 79.1
80.8 79.7
2.0
17
82.1
78.2
18
84.5
76.9
75.5
83.5 81.2
19
79.0 77.8
20
84.5
73.1
78.2 82.1
79.2 81.1 7.6
81.2 84.4 81.6 80.8…
Name:
Lab Time:
Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26
Contingency Analysis (Ch. 9)
In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to
evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop)
were more likely to suffer a fall in the next six months. I have tabulated the data below.
Answer the questions below. Please show your calculations on this or a separate sheet.
Did not stop walking to talk
Stopped walking to talk Totals
Suffered a fall
Did not suffer a fall
Totals
12
11
23
2
35
37
14
14
46
60
Quiz 7:
1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those
who did not stop walking vs. those who did stop walking. Interpret your result verbally.
Chapter 6 Solutions
Statistics for Business & Economics, Revised (MindTap Course List)
Ch. 6.1 - The random variable x is known to be uniformly...Ch. 6.1 - The random variable x is known to be uniformly...Ch. 6.1 - Delta Airlines quotes a flight time of 2 hours, 5...Ch. 6.1 - Prob. 4ECh. 6.1 - The driving distance for the top 100 golfers on...Ch. 6.1 - On average. 30-minute television sitcoms have 22...Ch. 6.1 - Suppose we are interested in bidding on a piece of...Ch. 6.2 - Using Figure 6.4 as a guide, sketch a normal curve...Ch. 6.2 - A random variable is normally distributed with a...Ch. 6.2 - Draw a graph for the standard normal distribution....
Ch. 6.2 - Given that z is a standard normal random variable,...Ch. 6.2 - Given that z is a standard normal random variable,...Ch. 6.2 - Given that z is a standard normal random variable,...Ch. 6.2 - Given that z is a standard normal random variable,...Ch. 6.2 - Given that z is a standard normal random variable,...Ch. 6.2 - Given that z is a standard normal random variable,...Ch. 6.2 - For borrowers with good credit scores, the mean...Ch. 6.2 - The average return for large-cap domestic stock...Ch. 6.2 - In an article about the cost of health care, Money...Ch. 6.2 - The average price for a gallon of gasoline in the...Ch. 6.2 - A person must score in the upper 2% of the...Ch. 6.2 - Television viewing reached a new high when the...Ch. 6.2 - The time needed to complete a final examination in...Ch. 6.2 - Trading volume on the New York Stock Exchange is...Ch. 6.2 - According to the Sleep Foundation, the average...Ch. 6.3 - A binomial probability distribution has p = .20...Ch. 6.3 - Assume a binomial probability distribution has p =...Ch. 6.3 - Although studies continue to show smoking leads to...Ch. 6.3 - An Internal Revenue Oversight Board survey found...Ch. 6.3 - Playing video and computer games is very popular....Ch. 6.3 - A Bureau of National Affairs survey found that 79%...Ch. 6.4 - Consider the following exponential probability...Ch. 6.4 - Consider the following exponential probability...Ch. 6.4 - Battery life between charges for the Motorola...Ch. 6.4 - The time between arrivals of vehicles at a...Ch. 6.4 - Comcast Corporation is the largest cable...Ch. 6.4 - Collinas Italian Caf in Houston, Texas, advertises...Ch. 6.4 - Do interruptions while you are working reduce your...Ch. 6 - A business executive, transferred from Chicago to...Ch. 6 - The NCAA estimates that the yearly value of a full...Ch. 6 - Motorola used the normal distribution to determine...Ch. 6 - During early 2012, economic hardship was...Ch. 6 - Cond Nast Traveler publishes a Gold List of the...Ch. 6 - Ward Doering Auto Sales is considering offering a...Ch. 6 - Is lack of sleep causing traffic fatalities? A...Ch. 6 - Assume that the test scores from a college...Ch. 6 - According to Salary Wizard, the average base...Ch. 6 - A machine fills containers with a particular...Ch. 6 - Consider a multiple-choice examination with 50...Ch. 6 - A blackjack player at a Las Vegas casino learned...Ch. 6 - The Information Systems Audit and Control...Ch. 6 - The website for the Bed and Breakfast Inns of...Ch. 6 - The American Community Survey showed that...Ch. 6 - The time (in minutes) between telephone calls at...Ch. 6 - Specialty Toys Specialty Toys, Inc., sells a...
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- Solve please and thank you!arrow_forward7. In a 2011 article, M. Radelet and G. Pierce reported a logistic prediction equation for the death penalty verdicts in North Carolina. Let Y denote whether a subject convicted of murder received the death penalty (1=yes), for the defendant's race h (h1, black; h = 2, white), victim's race i (i = 1, black; i = 2, white), and number of additional factors j (j = 0, 1, 2). For the model logit[P(Y = 1)] = a + ß₁₂ + By + B²², they reported = -5.26, D â BD = 0, BD = 0.17, BY = 0, BY = 0.91, B = 0, B = 2.02, B = 3.98. (a) Estimate the probability of receiving the death penalty for the group most likely to receive it. [4 pts] (b) If, instead, parameters used constraints 3D = BY = 35 = 0, report the esti- mates. [3 pts] h (c) If, instead, parameters used constraints Σ₁ = Σ₁ BY = Σ; B = 0, report the estimates. [3 pts] Hint the probabilities, odds and odds ratios do not change with constraints.arrow_forwardSolve please and thank you!arrow_forward
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