Chapter 6.3, Problem 28WE

To determine

To find: The division of the given term.

Answer to Problem 28WE

The division of the given termis $\frac{4\left(2-p^2\right)}{p^2}$.

Explanation of Solution

Given information:

The given term is,

  $\frac{8-2p^4}{3p^4}÷\frac{2+p^2}{6p^2}$

The given term is solved as,

  $\begin{array}{c}\frac{8-2p^4}{3p^4}÷\frac{2+p^2}{6p^2}=\frac{2\left(2^2-{\left(p^2\right)}^2\right)}{3p^4}\times \frac{6p^2}{\left(2+p^2\right)}\\ =\frac{2\left(\left(2+p^2\right)\left(2-p^2\right)\right)}{p^2}\times \frac{2}{\left(2+p^2\right)}\\ =\frac{4\left(2-p^2\right)}{p^2}\end{array}$

Therefore, the division of the given termis $\frac{4\left(2-p^2\right)}{p^2}$.