Calculating the Time of a Trip From a parking lot, you want to walk to a house on the beach. The house is located 1500 feet down a paved path that parallels the ocean, which is 500 feet away. See the illustration. Along the path you can walk 300 feet per minute, but in the sand on the beach you can only walk 100 feet per minute. The time T to get from the parking lot to the beach house expressed as a function of the angle θ shown in the illustration is T ( θ ) = 5 - 5 3 tan θ + 5 sin θ , 0 < θ < π 2 Calculate the time T if you walk directly from the parking lot to the house. [ Hint: tan θ = 500 1500 .]
Calculating the Time of a Trip From a parking lot, you want to walk to a house on the beach. The house is located 1500 feet down a paved path that parallels the ocean, which is 500 feet away. See the illustration. Along the path you can walk 300 feet per minute, but in the sand on the beach you can only walk 100 feet per minute. The time T to get from the parking lot to the beach house expressed as a function of the angle θ shown in the illustration is T ( θ ) = 5 - 5 3 tan θ + 5 sin θ , 0 < θ < π 2 Calculate the time T if you walk directly from the parking lot to the house. [ Hint: tan θ = 500 1500 .]
Solution Summary: The author explains how to calculate the time taken to get from the parking lot to the beach house by walking down a paved path that parallels the ocean.
Calculating the Time of a Trip From a parking lot, you want to walk to a house on the beach. The house is located 1500 feet down a paved path that parallels the ocean, which is 500 feet away. See the illustration. Along the path you can walk 300 feet per minute, but in the sand on the beach you can only walk 100 feet per minute.
The time
to get from the parking lot to the beach house expressed as a function of the angle
shown in the illustration is
,
Calculate the time
if you walk directly from the parking lot to the house.
Example(1):
(Adiabatic humidification and cooling of
air). Air has to be humidified and cooled
adiabatically in a honzontal spray chamber
with recirculated water. The active part of
the chamber is Im #2m #15 m long. Under
the operating conditions, the coefficient
of heat transfer is expected to be 1300
kcal/(hr)(m2)(°C). 200 m3/min of air at 60
°C and 1 atm pressure with a humidity of
0.018 kg water/kg dry air is to be blown
through the spray chamber. Calculate the
following
(a) the temperature and hunudity of the
exit air
(b) make-up water to be supplied, windage
and blow down are neglected
(c) the expected gas-phase mass transfer
coefficient, kya
(d) the temperature and humidity of the
exit air if an identical spray chamber is
added in series with
the existing one
O
find a simple formula fot the nth term of the following sequences
1, -2, 3, -4, 5, -6, ...
Calculate the first five terms of the following sequence
cn = n+(n+1)+(n+2)+···+(2n)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.