Explanation Method adopted: Graphical method. Assumption: Consider that the right side force as positive and left side as negative in horizontal components of forces. Consider that the upward force as positive and downward as negative in vertical components of forces. Consider that the clockwise moment as negative and anticlockwise moment as positive. Apply the Equation of equilibrium wherever applicable. Determine the reactions: Show the free-body diagram of the overhang beam as in Figure 1. Moment about point A : Determine the vertical reaction at point B by taking moment about point A . ∑ M A = 0 B y ( 3 ) − ( 1 2 × 4 × 3 × 2 3 × 3 ) − 4 × 3 × ( 3 + 3 2 ) = 0 3 B y − 12 − 54 = 0 B y = 22 kN Along the vertical direction: Determine the vertical reaction at point A by resolving the vertical component of forces. ∑ F y = 0 − A y + B y − 1 2 × 4 × 3 − 4 × 3 = 0 (1) Substitute 22 kN for B y in Equation (1). − A y + 22 − 6 − 12 = 0 A y = 4 kN Along the horizontal direction: Determine the horizontal reaction at point A by resolving the horizontal component of forces. ∑ F x = 0 A x = 0 Determine the shear force: The substitution of reaction values and moment included in the same calculation steps. Consider x from left end of the rod. Show the calculation of shear force values as follows: Shear force: Shear force at x = 0 : V | x = 0 ( Just left ) = 0 V | x = 0 ( Just right ) = − A y = − 4 kN Shear force at x = 3 m : V | x = 3 m ( Just left ) = − 4 − 1 2 × 4 × 3 = − 10 kN V | x = 3 m ( Just

9th Edition

ISBN: 9789810694364

Author: Russell C Hibbeler

Publisher: Pearson Education

See similar textbooks

Concept explainers

Bending Moment

In general, we can define the bending moment as the reaction induced when a certain amount of load or force is applied to an element which makes it bend.

Videos

Question

Chapter 6.2, Problem 6.22P

To determine

To draw: The shear and moment diagrams for the overhang beam.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 6.2, Problem 6.21P

Chapter 6.2, Problem 6.23P

Students have asked these similar questions

2.2 (A). If the maximum stress allowed in the copper of the cable of problem 2.1 is 60 MN/m2, determine the maximum tension which C3.75 kN.1 10:41 م

1.1 (A). A 25mm squarecross-section bar of length 300mm carries an axial compressive load of 50kN. Determine the stress set up ip the bar and its change of length when the load is applied. For the bar material E = 200 GN/m2. [80 MN/m2; 0.12mm.l

2.1 (A). A power transmission cable consists of ten copper wires each of 1.6 mm diameter surrounding three steel wires each of 3 mm diameter. Determine the combined E for the compound cable and hence determine the extension of a 30 m length of the cable when it is being laid with a tension of 2 kN. For steel, E200 GN/mZ; for copper, E = 100 GN/mZ. C151.3 GN/mZ; 9.6 mm.] 10:41 م

Chapter 6 Solutions

Mechanics Of Materials, Si Edition

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.