Explanation Given: A system of equations. 2 x + y + 3 z − 2 w = − 6 4 x + 3 y + z − w = − 2 x + y + z + w = − 5 − 2 x − 2 y − 2 z + 2 w = − 10 Calculation: Consider the system of equations. 2 x + y + 3 z − 2 w = − 6 4 x + 3 y + z − w = − 2 x + y + z + w = − 5 − 2 x − 2 y − 2 z + 2 w = − 10 Determine an augmented matrix and transform to reduced row echelon form. Further, determine the system variables. Form the augmented matrix and transform into row echelon form. [ 2 1 3 − 2 − 6 4 3 1 − 1 − 2 1 1 1 1 − 5 − 2 − 2 − 2 2 − 10 ] [ 1 1 2 3 2 − 1 − 3 4 3 1 − 1 − 2 1 1 1 1 − 5 − 2 − 2 − 2 2 − 10 ] R 1 → R 1 2 [ 1 1 2 3 2 − 1 − 3 0 1 − 5 3 10 1 1 1 1 − 5 − 2 − 2 − 2 2 − 10 ] R 2 → R 2 − 4 R 1 [ 1 1 2 3 2 − 1 − 3 0 1 − 5 3 10 0 1 2 − 1 2 2 − 2 − 2 − 2 − 2 2 − 10 ] R 3 → R 3 − R 1 [ 1 1 2 3 2 − 1 − 3 0 1 − 5 3 10 0 1 2 − 1 2 2 − 2 0 − 1 1 0 − 16 ] R 4 → R 4 + 2 R 1 [ 1 1 2 3 2 − 1 − 3 0 1 − 5 3 10 0 0 2 1 2 − 7 0 − 1 1 0 − 16 ] R 3 → R 3 − 1 2 R 2 Simplify further, [ 1 1 2 3 2 − 1 − 3 0 1 − 5 3 10 0 0 2 1 2 − 7 0 0 − 4 3 − 6 ] R 4 → R 4 + R 2 [ 1 1 2 3 2 − 1 − 3 0 1 − 5 3 10 0 0 1 1 4

MyLab Math with Pearson eText -- Standalone Access Card -- for Mathematics with Applications in the Management, Natural, and Social Sciences (12th Edition)

12th Edition

ISBN: 9780134856551

Author: Margaret L. Lial, Thomas W. Hungerford, John P. Holcomb, Bernadette Mullins

Publisher: PEARSON

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Chapter 6.2, Problem 59E

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To Calculate: The solution of the following system of equations.

2x+y+3z−2w=−64x+3y+z−w=−2x+y+z+w=−5−2x−2y−2z+2w=−10

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Chapter 6.2, Problem 58E

Chapter 6.2, Problem 60E

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A ladder 25 feet long is leaning against the wall of a building. Initially, the foot of the ladder is 7 feet from the wall. The foot of the ladder begins to slide at a rate of 2 ft/sec, causing the top of the ladder to slide down the wall. The location of the foot of the ladder, its x coordinate, at time t seconds is given by x(t)=7+2t. wall y(1) 25 ft. ladder x(1) ground (a) Find the formula for the location of the top of the ladder, the y coordinate, as a function of time t. The formula for y(t)= √ 25² - (7+2t)² (b) The domain of t values for y(t) ranges from 0 (c) Calculate the average velocity of the top of the ladder on each of these time intervals (correct to three decimal places): . (Put your cursor in the box, click and a palette will come up to help you enter your symbolic answer.) time interval ave velocity [0,2] -0.766 [6,8] -3.225 time interval ave velocity -1.224 -9.798 [2,4] [8,9] (d) Find a time interval [a,9] so that the average velocity of the top of the ladder on this…

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Chapter 6 Solutions

MyLab Math with Pearson eText -- Standalone Access Card -- for Mathematics with Applications in the Management, Natural, and Social Sciences (12th Edition)

Ch. 6.1 - Checkpoint1 Use the substitution method tosolve...Ch. 6.1 - Checkpoint 2 Use the elimination method to solve...Ch. 6.1 - Checkpoint 3 Solve the system of equations . Draw...Ch. 6.1 - Checkpoint 4 Solve the following system: Ch. 6.1 - Checkpoint 5 Solve the system Draw the graph of...Ch. 6.1 - Prob. 6CP Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Use substitution to solve each system. (See...Ch. 6.1 - Use substitution to solve each system. (See...

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The solution of the following system of equations. 2 x + y + 3 z − 2 w = − 6 4 x + 3 y + z − w = − 2 x + y + z + w = − 5 − 2 x − 2 y − 2 z + 2 w = − 10

Solution Summary: The author calculates the solution of the following system of equations. Determine an augmented matrix and transform to reduced row echelon form.

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To Calculate: The solution of the following system of equations.

2x+y+3z−2w=−64x+3y+z−w=−2x+y+z+w=−5−2x−2y−2z+2w=−10

Want to see the full answer?

Chapter 6 Solutions

The solution of the following system of equations. 2 x + y + 3 z − 2 w = − 6 4 x + 3 y + z − w = − 2 x + y + z + w = − 5 − 2 x − 2 y − 2 z + 2 w = − 10

Solution Summary: The author calculates the solution of the following system of equations. Determine an augmented matrix and transform to reduced row echelon form.

Videos

To Calculate: The solution of the following system of equations. 2x+y+3z−2w=−64x+3y+z−w=−2x+y+z+w=−5−2x−2y−2z+2w=−10

Want to see the full answer?

Chapter 6 Solutions

To Calculate: The solution of the following system of equations.

2x+y+3z−2w=−64x+3y+z−w=−2x+y+z+w=−5−2x−2y−2z+2w=−10