The cross product in ℝ n . Consider the vectors v → 2 , v → 3 , ... , v → n in ℝ n . The transformation T ( x → ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] is linear. Therefore, there exists a unique vector u → in ℝ n such that T ( x → ) = x → ⋅ u → for all x → in ℝ n . Compare this with Exercise 2.1 .43c. This vector u → is called the cross product of v → 2 , v → 3 , ... , v → n , written as u → = v → 2 × v → 3 × ⋯ × v → n . In other words, the cross product is defined by the fact that x → ⋅ ( v → 2 × v → 3 × ⋯ × v → n ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] , for all x → in ℝ n . Note that the cross product in ℝ n is defined for n − 1 vectors only. (For example, you can not form the cross product of just two vectors in ℝ 4 .) Since the ith component of a vector w → is e → ⋅ i w → . we can find the cross product by components as follows: ith component of v → 2 × v → 3 × ⋯ × v → n = e → i ⋅ ( v → 2 × ⋯ × v → n ) = det [ | | | | e → i v → 2 v → 3 ⋯ v → n | | | | ] a. When is v → 2 × v → 3 × ⋯ × v → n = 0 → ? Give your answer in terms of linear independence. b. Find e → 2 × e → 3 × ⋯ × e → n . c. Show that v → 2 × v → 3 × ⋯ × v → n is orthogonal to all the vectors v → i , for i = 2 , ... , n . d. What is the relationship between v → 2 × v → 3 × ⋯ × v → n and v → 3 × v → 2 × ⋯ × v → n ?(We swap the first two factors.) e. Express det [ v → 2 × v → 3 × ⋯ × v → n v → 2 × v → 3 × ⋯ × v → n ] in terms of ‖ v → 2 × v → 3 × ⋯ × v → n ‖ . f. How do we know that the cross product of two vectors in ℝ 3 , as defined here. is the same as the standard cross product in ℝ 3 ? See Definition A.9 of the Appendix.
The cross product in ℝ n . Consider the vectors v → 2 , v → 3 , ... , v → n in ℝ n . The transformation T ( x → ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] is linear. Therefore, there exists a unique vector u → in ℝ n such that T ( x → ) = x → ⋅ u → for all x → in ℝ n . Compare this with Exercise 2.1 .43c. This vector u → is called the cross product of v → 2 , v → 3 , ... , v → n , written as u → = v → 2 × v → 3 × ⋯ × v → n . In other words, the cross product is defined by the fact that x → ⋅ ( v → 2 × v → 3 × ⋯ × v → n ) = det [ | | | | x → v → 2 v → 3 ⋯ v → n | | | | ] , for all x → in ℝ n . Note that the cross product in ℝ n is defined for n − 1 vectors only. (For example, you can not form the cross product of just two vectors in ℝ 4 .) Since the ith component of a vector w → is e → ⋅ i w → . we can find the cross product by components as follows: ith component of v → 2 × v → 3 × ⋯ × v → n = e → i ⋅ ( v → 2 × ⋯ × v → n ) = det [ | | | | e → i v → 2 v → 3 ⋯ v → n | | | | ] a. When is v → 2 × v → 3 × ⋯ × v → n = 0 → ? Give your answer in terms of linear independence. b. Find e → 2 × e → 3 × ⋯ × e → n . c. Show that v → 2 × v → 3 × ⋯ × v → n is orthogonal to all the vectors v → i , for i = 2 , ... , n . d. What is the relationship between v → 2 × v → 3 × ⋯ × v → n and v → 3 × v → 2 × ⋯ × v → n ?(We swap the first two factors.) e. Express det [ v → 2 × v → 3 × ⋯ × v → n v → 2 × v → 3 × ⋯ × v → n ] in terms of ‖ v → 2 × v → 3 × ⋯ × v → n ‖ . f. How do we know that the cross product of two vectors in ℝ 3 , as defined here. is the same as the standard cross product in ℝ 3 ? See Definition A.9 of the Appendix.
Solution Summary: The author illustrates how linearly independent vectors are based on the given determinant.
The cross product in
ℝ
n
. Consider the vectors
v
→
2
,
v
→
3
,
...
,
v
→
n
in
ℝ
n
. The transformation
T
(
x
→
)
=
det
[
|
|
|
|
x
→
v
→
2
v
→
3
⋯
v
→
n
|
|
|
|
]
is linear. Therefore, there exists a unique vector
u
→
in
ℝ
n
such that
T
(
x
→
)
=
x
→
⋅
u
→
for all
x
→
in
ℝ
n
. Compare this with Exercise 2.1 .43c. This vector
u
→
is called the cross product of
v
→
2
,
v
→
3
,
...
,
v
→
n
, written as
u
→
=
v
→
2
×
v
→
3
×
⋯
×
v
→
n
. In other words, the cross product is defined by the fact that
x
→
⋅
(
v
→
2
×
v
→
3
×
⋯
×
v
→
n
)
=
det
[
|
|
|
|
x
→
v
→
2
v
→
3
⋯
v
→
n
|
|
|
|
]
,
for all
x
→
in
ℝ
n
. Note that the cross product in
ℝ
n
is defined for
n
−
1
vectors only. (For example, you can not form the cross product of just two vectors in
ℝ
4
.) Since the ith component of a vector
w
→
is
e
→
⋅
i
w
→
. we can find the cross product by components as follows: ith component of
v
→
2
×
v
→
3
×
⋯
×
v
→
n
=
e
→
i
⋅
(
v
→
2
×
⋯
×
v
→
n
)
=
det
[
|
|
|
|
e
→
i
v
→
2
v
→
3
⋯
v
→
n
|
|
|
|
]
a. When is
v
→
2
×
v
→
3
×
⋯
×
v
→
n
=
0
→
? Give your answer in terms of linear independence. b. Find
e
→
2
×
e
→
3
×
⋯
×
e
→
n
. c. Show that
v
→
2
×
v
→
3
×
⋯
×
v
→
n
is orthogonal to all the vectors
v
→
i
, for
i
=
2
,
...
,
n
. d. What is the relationship between
v
→
2
×
v
→
3
×
⋯
×
v
→
n
and
v
→
3
×
v
→
2
×
⋯
×
v
→
n
?(We swap the first two factors.) e. Express
det
[
v
→
2
×
v
→
3
×
⋯
×
v
→
n
v
→
2
×
v
→
3
×
⋯
×
v
→
n
]
in terms of
‖
v
→
2
×
v
→
3
×
⋯
×
v
→
n
‖
. f. How do we know that the cross product of two vectors in
ℝ
3
, as defined here. is the same as the standard cross product in
ℝ
3
? See Definition A.9 of the Appendix.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
eric
pez
Xte
in
z=
Therefore, we have
(x, y, z)=(3.0000,
83.6.1 Exercise
Gauss-Seidel iteration with
Start with (x, y, z) = (0, 0, 0). Use the convergent Jacobi i
Tol=10 to solve the following systems:
1.
5x-y+z = 10
2x-8y-z=11
-x+y+4z=3
iteration (x
Assi 2
Assi 3.
4.
x-5y-z=-8
4x-y- z=13
2x - y-6z=-2
4x y + z = 7
4x-8y + z = -21
-2x+ y +5z = 15
4x + y - z=13
2x - y-6z=-2
x-5y- z=-8
realme Shot on realme C30
2025.01.31 22:35
f
Use Pascal's triangle to expand the binomial
(6m+2)^2
Listen
A falling object travels a distance given by the formula d = 6t + 9t2 where d is in feet
and t is the time in seconds. How many seconds will it take for the object to travel
112 feet? Round answer to 2 decimal places. (Write the number, not the units).
Your Answer:
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