(a) Explanation Given Information: The expression is: ( y − 2 ) ( y + 1 ) . Formula used: When multiplying a binomial times a binomial, use the distributive property twice. The distributive property, a ( b + c ) = a b + a c Calculation: Consider the given expression, ( y − 2 ) ( y + 1 ) Use the distributive property to multiply y times ( y + 1 ) and then − 2 times ( y + 1 ) . ( y − 2 ) ( y + 1 ) = y ( y + 1 ) + ( − 2 ) (b) To determine To calculate: The simplified value of the expression ( 2 a + 3 ) ( a + 5 ) .

6th Edition

ISBN: 9780134179018

Author: Jamie Blair, John Tobey Jr., Jeffrey Slater, Jenny Crawford

Publisher: PEARSON

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Chapter 6.2, Problem 3QQ

(a)

To determine

To calculate: The simplified value of the expression (y−2)(y+1).

(b)

To determine

To calculate: The simplified value of the expression (2a+3)(a+5).

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Chapter 6.2, Problem 2QQ

Chapter 6.2, Problem 4QQ

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Chapter 6 Solutions

Prealgebra (6th Edition)

Ch. 6.1 - Fill in the blanks. To subtract two polynomials,...Ch. 6.1 - Fill in the blanks. To add two polynomials, we...Ch. 6.1 - Identify the terms of each polynomial. 5a26a+2b4+1 Ch. 6.1 - Identify the terms of each polynomial....Ch. 6.1 - Identify the terms of each polynomial. 6x63x33y1 Ch. 6.1 - Identify the terms of each polynomial. 2y33x24z38 Ch. 6.1 - Perform the operations indicated. (7y3)+(4y+9)Ch. 6.1 - Perform the operations indicated. (2x3)+(7x+6)Ch. 6.1 - Perform the operations indicated. (2a23a+6)+(4a2)Ch. 6.1 - Perform the operations indicated. (3c26c+3)+(2c7)

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The simplified value of the expression ( y − 2 ) ( y + 1 ) .

Solution Summary: The author explains how to calculate the simplified value of the expression (y-2).

To calculate: The simplified value of the expression (y−2)(y+1).

To calculate: The simplified value of the expression (2a+3)(a+5).

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Chapter 6 Solutions