LABORATORY MANUAL FOR HUMAN ANATOMY & PH
4th Edition
ISBN: 9781260254426
Author: Martin
Publisher: MCG
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Chapter 62, Problem 3.1CT
Assume that the genes for hairline and earlobes are on different pairs of homologous chromosomes. Determine the genotypes and
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In currant moths, their Light color is sex-linked and recessive (d) to dark color (D).
Question: What are the genotype and the phenotype of the parents if a certain cross yields ½ dark and ½ light colored females and all dark males?
Take note that female moths are heterogametic.
Fruit flies can have straight wings (S) or curly wings (s), and they can have be female XX or male XY.
(A) For a standard monohybrid cross (Ss ´ Ss), what proportion of the offspring will have the genotype ss? (Express the proportion as a simple fraction)
(B) For the following cross (SsXX ´ SsXY), what proportion of the offspring will have the genotype Ss? (Express the proportion as a simple fraction)
(C) What proportion will have the genotype XX? (Express the proportion as a simple fraction)
(D) What proportion will have the genotype SsXX? (Express the proportion as a simple fraction)SHOW YOUR WORK
Two plants in a cross were each heterozygous for two gene pairs (AB /ab) whose loci are linked and
30 map units (mu) apart. (Recall that 1 mu is equal to 1% recombination between two genes.)
Assuming that crossing over occurs during the formation of both male and female gametes and
that the A and B alleles are dominant, determine the phenotypic ratio of their offspring.
Part E: What proportion of the offspring of two
plants (both (AB/ab ) will be A - B- if the genes are 30
mu apart?
Part F: What proportion of the offspring of two
plants (both (AB/ab)) will be A - bb if the genes are 30
mu apart?
Part G: What proportion of the offspring of two
plants (both (AB/ab)) will be aaB- If the genes are 30
mu apart?
Part H: What proportion of the offspring of two
plants (both (AB/ab)) will be aabb if the genes are 30
mu apart?
Chapter 62 Solutions
LABORATORY MANUAL FOR HUMAN ANATOMY & PH
Ch. 62 - The term _________ is used for a person possessing...Ch. 62 - The term _________ is used for the appearance of...Ch. 62 - The _________ is a genetic tool to simulate all...Ch. 62 - Prob. 4PLCh. 62 - Which of the following represents a dominant human...Ch. 62 - An attached earlobe is considered a recessive...Ch. 62 - A diploid chromosome number of 46 and a haploid...Ch. 62 - The possession of freckles is considered a...Ch. 62 - Single penny tossed 20 times and counting heads...Ch. 62 - Determine the results from a cross of a mother who...
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- During the process of Meiosis an individual's alleles for each trait are independently sorted to make unique gametes. A person is heterozygous for the Freckles phenotype (Ff) and also heterozygous for the PTC-tasting phenotype (Tt). This person's genotype for these two traits is represented as FfTt. A) How many unique gametes could be produced by this individual if you consider these two traits? B) List the different allele combinations that could result.arrow_forwardIn the following cross, imagine that you have a female fly that has two Xs and one Y due to a nondisjunction event in her mother's germ cells. Draw out what the possible gametes are for both the female and the male and also a Punnett square showing the genotypes, phenotypes, and sex of the possible flies as a result of this cross. You do not need to provide the probabilities of each of these. Red-eyed wi C Ở Red-eyed wt XX Y X Y Meiosisarrow_forwardGene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross. A) List all of the possible gametes (eggs) that could be produced by an individual with the genotype: aabb B) List all of the possible gametes (sperm) that could be produced by an individual with the genotype: AaBB C) Fill out a Punnett square for the dihybrid cross cross between the two individuals listed above (aabb x AaBB). What percent of the offspring from this cross would have the dominant phenotype for both traits?arrow_forward
- In fruit flies, eye color is carried on the X chromosome. The allele for red eyes is dominant over its recessive allele, white eyes. -Cross a heterozygous female to a white-eyed male 1st Question to answer ---- How many genotypes are possible among the offspring? 2nd Question to answer ---- How many phenotypes are possible among the offspring? 3rd Question to answer ---- What is the probability of getting a red-eyed male? 4th Question to answer ---- What is the probability of getting a white-eyed male? 5th Question to answer ---- What is the probability of getting a red-eyed female? 6th Question to answer ---- What is the probability of getting a white-eyed female? 7th Question to answer ---- What is the probability of getting a red-eyed offspring? 8th Question to answer ---- What is the probability of getting a white-eyed offspring?arrow_forwardDraw a Punnett square for the dihybrid cross. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage.arrow_forwardTwo plants in a cross were each heterozygous for two gene pairs (AB/ab) whose loci are linked and 10 map units (mu) apart. (Recall that 1 mu is equal to 1% recombination between two genes.) Assuming that crossing over occurs during the formation of both male and female gametes and that the A and B alleles are dominant, determine the phenotypic ratio of their offspring. Part D If the two genes are 15 mu apart and the plant is (Ab/aB), what proportion of gametes from a signal plant will be ab? Part E What proportion of the offspring of two plants ( both (Ab/aB)) will be A_B_ if the genes are 15 mu apart? Part F What proportion of the offspring of two plants ( both (Ab/aB)) will be A_bb if the genes are 15 mu apart? Part G What proportion of the offspring of two plants ( both (Ab/aB)) will be aaB_ if the genes are 15 mu apart? Part H What proportion of the offspring of two plants ( both (Ab/aB)) will be aabb if the genes are 15 mu apart? How would I solve these?arrow_forward
- In a testcross for two genes, what types of gametes are produced with (a) complete linkage, (b) independent assortment, and (c) incomplete linkage?arrow_forwardAn individual that is homozygous AABBcc is crossed to an individual that is homozygous aabbCC producing F1 individuals with genotype AaBbCc. Assume that the A, B, and C loci are all on the same chromosome. One chromatid at the start of meiosis (before crossing over) has the alleles A, B, and c. What alleles are on its sister chromatid? What alleles are on the homolog? Group of answer choices A. Sister chromatid ABc, Homolog no way to tell B. Sister chromatid ABC, Homolog abc C. Sister chromatid ABc, Homolog abC D. Sister chromatid abC, Homolog ABcarrow_forwardAssume that the trihybrid cross AABBrr x aabbRR is made in a plant species. Assume that A and B are dominant alleles, but there is no dominance effect of alleles at the R locus. a) How many different gametes are possible in the F1generation? What are the genotypes of these gametes? b) What is the probability of the parental aabbRR genotype in the F2 progeny? c) What proportion of the F2 progeny would be expected to be homozygous for all three genes?arrow_forward
- The image shows a pair of homologous chromosomes from a single parent before gamete production. M1 and M2 are maternal chromosomes, while P1 and P2 are paternal chromosomes. Two traits are shown: D represents seed color (D – green, d – yellow), while F represents flower color (F – purple, f – white). These two traits follow the patterns of basic Mendelian genetics. During crossing-over between the M2 F allele and the P1 f allele, a mutation occurred and the portion of P1 did not reattach to the chromosome. Which of the following explains what would happen to the proportion of white flowers in a population resulting from this mutation? A - There would be an increase in the proportion of white flowers because the f allele is distributed to more gametes. B - There would be a decrease in the proportion of white flowers because the f allele is not distributed to as many gametes. C - There would be an increase in the proportion of white flowers because the f allele would not be masked by the…arrow_forwardDraw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and…arrow_forwardDesign a scheme for each possible outcome of the cross in figure and label the parental and and recombinant progeny.arrow_forward
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