12th Edition

ISBN: 9780321836960

Author: Mario F. Triola

Publisher: PEARSON

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A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

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Textbook Question

Chapter 6.2, Problem 29BSC

Standard Normal Distribution. In Exercises 17–36, assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. In each case, draw a graph and find the probability of the given scores. If using technology instead of Table A-2, round answers to four decimal places.

29. Between and −2.20 and 2.50

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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Chapter 6.2, Problem 28BSC

Chapter 6.2, Problem 30BSC

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Chapter 6 Solutions

Elementary Statistics

Ch. 6.2 - Normal Distribution When we refer to a normal...Ch. 6.2 - Normal Distribution A normal distribution is...Ch. 6.2 - Standard Normal Distribution Identify the...Ch. 6.2 - Notation What does the notation Z indicate?Ch. 6.2 - Continuous Uniform Distribution. In Exercises 58,...Ch. 6.2 - Continuous Uniform Distribution. In Exercises 58,...Ch. 6.2 - Continuous Uniform Distribution. In Exercises 58,...Ch. 6.2 - Continuous Uniform Distribution. In Exercises 58,...Ch. 6.2 - Prob. 9BSC Ch. 6.2 - Standard Normal Distribution. In Exercises 912,...

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Solution Summary: The author explains that the probability of the bone density test score between –2.20 and 2.50 is 0.9799.

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