To determine To calculate: The solution of the provided rational expression x 2 − 2 x 2 + 6 x − 7 − − 4 x + 19 x 2 + 6 x − 7 Explanation Given Information: The provided rational expression is x 2 − 2 x 2 + 6 x − 7 − − 4 x + 19 x 2 + 6 x − 7 . Formula used: Follow the steps as mentioned below to subtract the rational expression with a common denominator, Step 1: Subtract the provided rational expression by the use of rule given by, a c − b c = a − b c , c ≠ 0 Step 2: Simplify the expression obtained from step 1 as required. Distributive property is given as, a ( b + c ) = a b + a c Calculation: Consider the provided rational expression, x 2 − 2 x 2 + 6 x − 7 − − 4 x + 19 x 2 + 6 x − 7 Subtract the provided rational expression by the use of subtraction rule given above for rational expression with common denominator, x 2 − 2 x 2 + 6 x − 7 − − 4 x + 19 x 2 + 6 x − 7 = ( x 2 − 2 ) − ( − 4 x + 19 ) x 2 + 6 x − 7 Now remove brackets with the help of distributive property and then combine the like terms, x 2 − 2 x 2 + 6 x − 7 − − 4 x + 19 x 2 + 6 x − 7 = ( x 2 − 2 ) − ( − 4 x + 19 ) x 2 + 6 x − 7 = x 2 − 2 + ( − 1 ) ( − 4 x + 19 ) x 2 + 6 x − 7 =

Intermediate Algebra For College Students (10th Edition)

10th Edition

ISBN: 9780134758992

Author: Allen R. Angel, Dennis Runde

Publisher: PEARSON

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Chapter 6.2, Problem 15ES

To determine

To calculate: The solution of the provided rational expression x2−2x2+6x−7−−4x+19x2+6x−7

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Chapter 6.2, Problem 14ES

Chapter 6.2, Problem 16ES

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Chapter 6 Solutions

Intermediate Algebra For College Students (10th Edition)

Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Prob. 6ES Ch. 6.1 - Prob. 7ES Ch. 6.1 - Prob. 8ES Ch. 6.1 - Prob. 9ES Ch. 6.1 - Prob. 10ES

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