To determine To calculate: The simplified form of the expression 1 x 2 − 3 x − 18 + 2 x 2 − 2 x − 15 3 x 2 − 11 x + 30 + 1 x 2 − 9 x + 20 . Explanation Given Information: The provided equation is 1 x 2 − 3 x − 18 + 2 x 2 − 2 x − 15 3 x 2 − 11 x + 30 + 1 x 2 − 9 x + 20 . Formula used: A complex fraction of the form a b c d can be simplified by multiplying the numerator with the reciprocal of the denominator. Therefore, a b c d = a b ÷ c d = a b × d c = a d b c Calculation: Consider the expression 1 x 2 − 3 x − 18 + 2 x 2 − 2 x − 15 3 x 2 − 11 x + 30 + 1 x 2 − 9 x + 20 . Solve the numerator, 1 x 2 − 3 x − 18 + 2 x 2 − 2 x − 15 = 1 ( x − 6 ) ( x + 3 ) + 2 ( x + 3 ) ( x − 5 ) = x − 5 + 2 x − 12 ( x − 6 ) ( x + 3 ) ( x − 5 ) = 3 x − 17 ( x − 6 ) ( x + 3 ) ( x − 5 ) Solve the denominator, 3 x 2 − 11 x + 30 + 1 x 2 − 9 x + 20 = 3 ( x − 5 ) ( x − 6 ) + 1 ( x − 5 ) ( x − 4 ) = 3 ( x − 4 ) + x − 6 ( x − 5 ) ( x − 6 ) ( x − 4 ) = 4 x − 18 ( x − 5 ) ( x − 6 )

Intermediate Algebra For College Students (10th Edition)

10th Edition

ISBN: 9780134758992

Author: Allen R. Angel, Dennis Runde

Publisher: PEARSON

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Question

Chapter 6, Problem 58RE

To determine

To calculate: The simplified form of the expression 1x2−3x−18+2x2−2x−153x2−11x+30+1x2−9x+20.

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Chapter 6, Problem 57RE

Chapter 6, Problem 59RE

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Chapter 6 Solutions

Intermediate Algebra For College Students (10th Edition)

Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Fill in the blanks with the appropriate word,...Ch. 6.1 - Prob. 6ES Ch. 6.1 - Prob. 7ES Ch. 6.1 - Prob. 8ES Ch. 6.1 - Prob. 9ES Ch. 6.1 - Prob. 10ES

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