(a) Explanation Write the expression for heat loss by iron. H i = m i c i ( T 1 − T 2 ) (I) Here, the heat loss by iron is H i , mass of iron is m i , specific heat of iron is c i , initial temperature of iron is T 1 , and final temperature at equilibrium is T 2 . Write the expression for heat gain by oil. H o = m o c o ( T 2 − T 3 ) (II) Here, the heat gain by oil is H o , the mass of oil is m o , the specific heat of oil is c o and initial temperature of oil is T 3 . The heat loss by iron is equal to heat gain by oil. Apply energy balance, H i = H o (III) Substitute m i c i ( T 1 − T 2 ) for H i and m o c o ( T 2 − T 3 ) for H o in Equation (III). m i c i ( T 1 − T 2 ) = m o c o ( T 2 − T 3 ) m i c i T 1 − m i c i T 2 = m o c o T 2 − m o c o T 3 ( m o c o + m i c i ) T 2 = m i c i T 1 + m o c o T 3 T 2 = m i c i T 1 + m o c o T 3 ( m o c o + m i c i ) (IV) Conclusion: Convert initial temperature of iron from Fahrenheit to Rankine. T 1 = 700 ° F = ( 700 ° F + 459 (b) To determine The entropy produced within the tank.

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Chapter 6.13, Problem 60P

(a)

To determine

The final temperature of iron in quenching process.

(b)

To determine

The entropy produced within the tank.

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Chapter 6.13, Problem 59P

Chapter 6.13, Problem 61P

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