(a) Explanation The following Figure-(1) shows the T − s diagram for expansion in turbine. Figure-(1) In Figure-(1), the process 1-2 is actual expansion in turbine and process 1-2s is isentropic expansion in turbine. Calculate the work done per unit mass. W ˙ = h 1 − h 2 (I) Here, the work done per unit mass is W ˙ , the enthalpy at sate 1 is h 1 and enthalpy at state 2 is h 2 . Conclusion: Refer to Table A-3 “Properties of saturated water” At pressure 0.10 bar . Obtain enthalpy of saturated liquid ( h f 2 ) as 191.83 kJ/kg and enthalpy of saturated vapor ( h g 2 ) as 2584.7 kJ/kg corresponding to state 2 . Write the expression for enthalpy at state 2 . h 2 = h f 2 + x 2 ( h g 2 − h f 2 ) (II) Here, enthalpy at state 2 is h 2 and dryness fraction at state 2 is x 2 . Substitute 191.83 kJ/kg for h f 2 , 0.9 for x 2 and 2584.7 kJ/kg for h g 2 in Equation (II). h 2 = 191.83 kJ/kg + ( 0.9 ) ( 2584.7 kJ/kg − 191.83 kJ/kg ) = 191 (b) To determine The amount of entropy produced per unit mass. (c) To determine The isentropic efficiency of turbine.

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118412930

Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey

Publisher: WILEY

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Chapter 6.13, Problem 134P

(a)

To determine

The work done per unit mass.

(b)

To determine

The amount of entropy produced per unit mass.

(c)

To determine

The isentropic efficiency of turbine.

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Chapter 6.13, Problem 133P

Chapter 6.13, Problem 135P

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