Explanation Write the lighting power saved in refrigerator. lighiting power saved = l light bulb − l energy-efficient bulb (I) Here, the energy consume by the light bulb is l light bulb and the energy consume by the energy-efficient bulb is l energy-efficient bulb . Write the lighting energy saved a year by the energy efficient bulb. lighting energy saved = ( lighting power saved ) × ( operating hours ) (II) Write the amount of energy saved in refrigeration. Refrigeration energy saved= lighting energy saved COP (III) Here, the coefficient of performance of the refrigeration is COP. Write the total energy saved by the energy efficient light bulb. Total energy saved = ( lighting energy saved + refrigeration energy saved ) (IV) Write the amount of money saved by the energy efficient light bulb. Money saved = ( total energy saved ) × ( unit cost of energy ) (V) Conclusion: Substitute 40 W for l light bulb and 18 W for l energy-efficient bulb in Equation (I). lighiting power saved = ( 45 W ) − ( 18 W ) = 22 W Substitute 22 W for lighting power saved and 60 h / year for operating hours in Equation (II). lighting energy saved = ( 22 W ) × ( 60 h / year ) = 1320 Wh / year = 1320 Wh / year × ( 1 kWh / year 1000 Wh / year ) = 1

8th Edition

ISBN: 9780073398174

Author: Yunus A. Cengel Dr., Michael A. Boles

Publisher: McGraw-Hill Education

See similar textbooks

Concept explainers

Applied Fluid Mechanics

A fluid is a substance that is continuously deformed by the application of shear stress. The rate of deformation of a fluid depends on its viscosity. The fluid tries to flow when it interacts with some other system.

Videos

Question

Chapter 6.11, Problem 116P

To determine

The energy savings of the proposed light bulb justify its cost.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 6.11, Problem 115P

Chapter 6.11, Problem 117P

Students have asked these similar questions

A gearbox has permanent shaft positions defined by the bearing mounting positions, but the gear ratio can be changed by changing the number of teeth in the pinion and gear. To achieve similar power transmission ability for different gear ratios, a manufacturer chooses to have the same module for two different gearboxes. One of the gaerboxes has a pinion with 22 teeth, a gear with 68 teeth, and a center distance of 225mm. How large is the gear module and which gear ratios are possible for a pinion with 22 or more teeth using the same module?

A gear train has a 50.3 mm circular pitch and a 25 degree pressure angle and meshes with a pinion having 12 teeth Design this gear train to minimize its volume and the total number of teeth. Obtain the pitch diameters the number of teeth the speed ratio the center distance and the module of this gear train. The gearbox housing has a diameter of 620mm

Handwritten solution required ,strictly do not use CHATGPT. MECHANICAL ENGG

Chapter 6 Solutions

Thermodynamics: An Engineering Approach

Ch. 6.11 - Describe an imaginary process that violates both...Ch. 6.11 - Describe an imaginary process that satisfies the...Ch. 6.11 - Describe an imaginary process that satisfies the...Ch. 6.11 - An experimentalist claims to have raised the...Ch. 6.11 - Prob. 5P Ch. 6.11 - Consider the process of baking potatoes in a...Ch. 6.11 - What are the characteristics of all heat engines?Ch. 6.11 - What is the KelvinPlanck expression of the second...Ch. 6.11 - Is it possible for a heat engine to operate...Ch. 6.11 - Baseboard heaters are basically electric...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.