Chapter 6.1, Problem 37E

In Exercises 9-50, find the indefinite integral

37. ${\displaystyle \int (\frac{{\text{u}}^3+2{\text{u}}^2-\text{u}}{3\text{u}}\text{) }\text{du}}$

Hint: $\frac{{\text{u}}^3+2{\text{u}}^2-\text{u}}{3\text{u}}=\frac{1}{3}{\text{u}}^2+\frac{2}{3}\text{u}-\frac{1}{3}$